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Andreyy89
3 years ago
7

Last year, Kristen went bowling several times and earned an average score of 84 points. This year, she improved her score to an

average of 105 points. What is the percent of increase in Kristen's average score?
Mathematics
1 answer:
Viktor [21]3 years ago
8 0

Answer:

percentage increase in Kristen's average score is = 25%

Step-by-step explanation:

Given:-

- The last year score, Si = 84 points

- This year score, Sf = 105 points

Find:-

What is the percent of increase in Kristen's average score?

Solution:-

- We are to determine the percentage increase in Kristen's average score from last year.

- The relation to develop percentage increase "%inc" is given by:

                              %inc = \frac{Sf - Si }{Si}*100

- plug in the values:

                              inc = \frac{105 - 84 }{84}*100\\\\inc = 25

- The percentage increase in Kristen's average score is = 25%

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3 years ago
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<h3>Conner work is correct. Jana work is wrong</h3>

<em><u>Solution:</u></em>

<em><u>Given that,</u></em>

<em><u>Conner and Jana are multiplying:</u></em>

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We have to check if this work is correct

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From given,

(3^56^8)(3^96^{10})\\\\3^5 \times 6^8 \times 3^9 \times 6^{10}

Use the following law of exponent

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Therefore,

3^5 \times 6^8 \times 3^9 \times 6^{10} = 3^5 \times 3^9 \times 6^8 \times 6^{10} = 3^{5+9} \times 6^{8+10} = 3^{14} \times 6^{18}

<em><u>Given Jana's work is:</u></em>

(3^56^8)(3^96^{10}) = 3^{5.9}6^{8.10} = 3^{45}6^{80}

This is incorrect

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7 0
3 years ago
NEED HELP ASAP, WORTH 80PTS
sp2606 [1]

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This is because the expression can be simplified to get the same result. -1+2log_4((1/4)x)

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Answer:
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Step-by-step explanation:
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