4 years ago

I need help ASAP .......

Mathematics

1 answer:

pickupchik [31]4 years ago

4 0

Answer:

Step-by-step explanation:

its 0 because if you add 29 and 31 and 10 youll need to simplify and it wont be very exact so you would have to fracertize and it would equle 0

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An exit poll of 1000 randomly selected voters found that 515 favored measure A. a. Construct a 99% confidence interval for the s

never [62]

Answer:

Step-by-step explanation:

Given that an exit poll of 1000 randomly selected voters found that 515 favored measure A.

Sample proportion p = $\frac{515}{1000} =0.515$

$q=1-0.515 =0.485\\n =1000\\SE = \sqrt{\frac{pq}{n} } \\=0.158\\$

Margin of error 99% = 2.58*SE

= $2.58*0.0158\\=0.0408$

99% confidence interval = $(0.515-0.0408, 0.515+0.0408)\\= (0.474, 0.556)$

------------------------

$H_0: p =0.5\\H_a: p >0.5\\$

(Right tailed test)

STd error = $\sqrt{\frac{0.5*0.5}{1000} } \\=0.0158$

Test statistic Z = p diff/std error = $\frac{0.015}{0.0158} \\\\=0.9487$

p value = 0.1714

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Your welcome

Sincerely, h o n e y

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