Sine (34) = opposite / 99
opposite side = .55919 * 99
opposite side =
<span>
<span>
<span>
55.35981
</span>
</span>
</span>
Adjacent side² = 99² - 55.35981²
Adjacent side² =
<span>
<span>
</span></span>
<span>
<span>
<span>
9,801
</span>
</span>
</span>
-<span><span><span>3,064.7085632361
</span>
</span>
</span>
<span><span><span>Adjacent side² =
6,736.29
</span>
</span>
</span>
Adjacent side =
<span>
<span>
<span>
82.0749
</span></span></span>
1/3 of 2/3
Just multiply them
1/3 x 2/3 = 2/9
Given
- f(n) values for n=1,2,3,4
- possible candidates for the function
Solution:
Method: Evaluate some of the values, for each function. A function with ANY value not matching the given f(n) values will be rejected.
N=1, f(n)=4
f(1)=4-3(1-1)=4
f(1)=4+3^(1+1)=4+3^2=4+9=13 ≠ 4 [rejected]
f(1)=4(3^(n-1))=4(3^0)=4
f(1)=3(4^(n-1))=3(4^0)=3*1=3 [rejected]
N=2, f(n)=12
f(1)=4-3(2-1)=4-3(1)=1 ≠ 12 [rejected]
[rejected]
f(1)=4(3^(2-1)=4*3^1=4*3=12
[rejected]
Will need to check one more to be sure
N=3, f(n)=3
[rejected]
[rejected]
f(3)=4(3^(n-1))=4(3^(3-1))=4(3^2)=4*9=36 [Good]
[rejected]
Solution: f(n)=4(3^(n-1))
The atomic mass of an atom tells us about how much the atom weighs.
Option A
<u>Step-by-step explanation:</u>
The atomic mass of an atom tells us about the weight of the atoms. An atom can be represented using the mass number denoted as A and atomic number denoted by Z. As atomic number is the number of protons present in the atom, mass number denotes the sum of protons and neutrons present in the atom.
So, the mass number will be approximately equal to the atomic mass. It can be also stated that atomic mass represents the weight of the atoms. The elements are arranged in the increasing order of their atomic mass in the periodic table.
2:10 is equivalent. To get the answer you multiply 1 & 2 by their LCM (least common multiple) , which is 2, and that's how you get the answer, and to check to see if it's right just divide by 2 but if you know multiples of 1 and 5 then you could've easily looked at the answer choices to find your answer.
hopefully this helps
