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german
3 years ago
14

20 points to help with this

Mathematics
1 answer:
Vikentia [17]3 years ago
6 0

Answer:

Help what?

Step-by-step explanation:

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Given the function f(x) = 2x, find the value of f−1(32).
Oliga [24]

Answer:

it is -30

Step-by-step explanation:

you would divide both sides by x,then f=2

using PEMDAS we come to -30

5 0
3 years ago
If 1/4c = 1/2d = 4e = 8, what is the value of c + d + e?
Natali5045456 [20]

Answer:c=1/32 d=1/16 e=2

C+d+e=1/32+1/16+2=35/16

Step-by-step explanation:

Solve for c

1/4c =8

C=1/32

1/2d=8

d=1/16

4e=8

e=2

6 0
4 years ago
A bearing, measured at 1.234 inches with a caliper, must be replaced. Since the bearings are sized in 64ths of an inch, find the
Ganezh [65]
We have
1.234 in-----> 1+(0.234) in

we know that
1/64=0.015625
so
0.234/0.015625=14.98-----> 15
15/64-----> 0.234

therefore
1.234 in is equal to -----------> 1 15/64 in

the answer is
1 15/64 in
7 0
3 years ago
Given: AB / BC
Ahat [919]

1. given

2. perpendicular lines makes a right angle

5. definition of complementary angles

sorry bout the others. idk how to word it so hopefully what I gave you helps

8 0
3 years ago
I have some cheese. I used
hram777 [196]
<h3>Answer:     2500 grams</h3>

============================================

Work Shown:

A = amount of grams of cheese you had originally

B = (2/5)*A = amount of cheese you use up after day 1

C = (3/5)*A = amount of cheese you have left over after day 1

note how B and C add back up to 'A'.

This is because 2/5+3/5 = 5/5 = 1, so,

B+C = (2/5)A+(3/5)A = (2/5+3/5)A = 1*A = A

--------------

D = (2/5)*C = amount of cheese you use up after day 2

E = (3/5)*C = amount of cheese left over after day 2

the variables D and E add up to C

we are told that there are 900 grams of cheese left after day 2, so E = 900

--------------

E = (3/5)*C

(3/5)*C = E

(3/5)*C = 900 ... Plug in E = 900

3C = 900*5 .... multiply both sides by 5

3C = 4500

C = 4500/3 .... divide both sides by 3

C = 1500

This means you had 1500 grams of cheese after day 1

-------------

C = (3/5)*A

(3/5)*A = C

(3/5)*A = 1500 ... plug in C = 1500

3A = 1500*5 ... multiply both sides by 5

3A = 7500

A = 7500/3 .... divide both sides by 3

A = 2500

-----------

<h3>You started off with 2500 grams of cheese.</h3>

After day 1, you use up (2/5)*2500 = 1000 grams of cheese and have 2500-1000 = 1500 grams left over.

After day 2, you use up (2/5)*1500 = 600 grams of cheese and have 1500-600 = 900 grams left over.

The answer is confirmed.

6 0
4 years ago
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