Answer:
-2(x^2+2)
Step-by-step explanation:
1. x^2-3x^2-4
= -2x^2-4
2. -2(x^2+2) factor completely :)
Answer:
where's the table. on és la taula?
Step-by-step explanation:
Answer:
2x^2(3x^2-2x-1)
Step-by-step explanation:
12x^4 - 8x^3 - 4x^2
everything is a multiple of 4 so divide the whole thing by 4
12x^4 - 8x^3 - 4x^2/4= 3x^4-2x^3-1x^2
write it in disturbed form
2(3x^4-2x^3-1x^2)
now if u see we can see that the X will be same, so we also have to factor it out and 2 is the exponent that all can give
2x^2(3x^2-2x-1)
I'm going to assume that you are asking how a number can have two factors.
So, a factor is an integer (non-fractional/decimal number) you multiply by another integer to get the actual number.
Well, let's look at the number 4. The number four has the following factors:
1, 2, 4
In a 'rainbow' style, you match the two outer numbers, then the two next inner numbers, and so on.
Because the number '2' is the one in the center and there is no other number to multiply it by, it must multiply by itself to reach the number 4.
Well, you must have two numbers to actually multiply together, so every number has two factors: 1, and itself (except for 0).
I hope this helps, and good luck :)
