Test a pair from each table by substituting their values into the given equation and solving.
A) y = 2x + 1 .......... 2 = 2(0) + 1 .......... 2 ≠ 1
B) y = 2x + 1 .......... 1 = 2(0) + 1 .......... 1 = 1
C) y = 2x + 1 .......... -1 = 2(0) + 1 .......... -1 ≠ 1
D) y = 2x + 1 .......... -2 = 2(0) + 1 .......... -2 ≠ 1
The only pair that satisfied the equation was from answer choice B. Therefore, B is the correct answer.
The two equations graphs intersect and the points where they are touching are belonging to both graphs therefore solutions for both equations.
(2) points (x,y) are
(-1,0) (-1)^2. +0^2=1; 1=1 ✔️
0=-1+1; 0=0✔️
(0, 1). (0)^2. +1^2=1; 1=1 ✔️
1=0+1; 1=1 ✔️
Answer:
I think answer is 3
Step-by-step explanation:
BD = DA
BE = EC
Now, BD/BE = DA/EC
or, x + 5/2x = 4/3
or, 3x + 15 = 8x
or, 15 = 8x - 3x
or, 15 = 5x
or, 15/5 = x
or, 3 = x
Therefore x = 3 <u>Ans</u>
Answer:
-2
Step-by-step explanation:
- 5x + 8 = 18
Take + 8 to the right hand side, it turns negative i.e -8
-5x = 18 - 8
-5x = 10
Divide both sides by the coefficient of x which is -5
-5x/5 = 10/-5
x = -2
