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3 years ago

8

Identify BR rounded to the nearest tenth. HELP PLEASE!!

1 answer:

ahrayia [7]3 years ago

5 0

Answer:

<h2>BR ≈ 49.0</h2>

Step-by-step explanation:

Use cosine:

$cosine=\dfrac{adjacent}{hypotenuse}$

We have

$adjacent=42\\hypotenuse=BR\\\alpha=31^o$

$\cos31^o\approx0.8572$

Substitute:

$\dfrac{42}{BR}=0.8572$

$\dfrac{42}{BR}=\dfrac{8,572}{10,000}$ <em>cross multiply</em>

$8,572BR=420,000$ <em>divide both sides by 8,572</em>

$BR=\dfrac{420,000}{8,572}$

$BR\approx49.0$

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Solve the inequality 3>5-b

victus00 [196]

Answer:

I'm pretty sure its b>2

Step-by-step explanation:

Step 1: Simplify both sides of the inequality.

3>−b+5

Step 2: Flip the equation.

−b+5<3

Step 3: Subtract 5 from both sides.

−b+5−5<3−5

−b<−2

Step 4: Divide both sides by -1.

-b/-1 < -2/-1

Answer:

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2 years ago

547321 rounded to nearest one thousand

Sphinxa [80]

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3 years ago

Write and equati9n of a l8ne that passes through (1,-2) and is perpendicular to -4x+7y=21

yarga [219]

Given:

A line passes through (1,-2) and is perpendicular to $-4x+7y=21$ .

To find:

The equation of that line.

Solution:

We have, equation of perpendicular line.

$-4x+7y=21$

Slope of this line is

$m_1=-\dfrac{\text{Coefficient of x}}{\text{Coefficient of y}}$

$m_1=-\dfrac{-4}{7}$

$m_1=\dfrac{4}{7}$

Product of slope of two perpendicular lines is -1.

$m_1\times m_2=-1$

$\dfrac{4}{7}\times m_2=-1$

$m_2=-\dfrac{7}{4}$

Now, slope of required line is $-\dfrac{7}{4}$ and it passes through (1,-2). So, the equation of line is

$y-y_1=m(x-x_1)$

where, m is slope.

$y-(-2)=-\dfrac{7}{4}(x-1)$

$4(y+2)=-7(x-1)$

$4y+8=-7x+7$

$4y+7x=7-8$

$7x+4y=-1$

Therefore, the equation of required line is $7x+4y=-1$ .

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2 years ago

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Which mathematical equation represents the solution for k in the equation h + 3 = jk + 6k ?

Tomtit [17]

Answer:

The answer is<u> D.</u> h+3/j+6.

Step-by-step explanation:

Given:

The equation h + 3 = jk + 6k.

Now, to get the mathematical expression.

$h + 3 = jk + 6k$

So, taking $k$ common on R.H.S we get:

$h + 3 = k(j + 6)$

Then, dividing both sides by $j+6$ we get:

$\frac{h+3}{j+6} =k$

Thus,

$k=\frac{h+3}{j+6}$

Therefore, the answer is D. h+3/j+6.

5 0

3 years ago