Let us start subtracting 3 cos theta both sides so that we may get all theta terms on left side only
It is now : 4 cos theta - 3 cos theta = - (sqrt3)/ 2
1 cos theta = -( sqrt 3 ) /2
we know cos (pi-x)= - cos x And cos (pi+ x)= - cos (x)
********* let us first use :
- Cos ( pi - theta) = - ( sqrt 3 )/2
this implies cos (pi- theta )= (sqrt 3) /2
cos ( pi - theta )= cos (pi /6)
pi- theta = pi/6
pi- pi/6 = theta
5 pi/6 = theta
one of teh answer is 5 pi/6 . another value of theta would be :
(2pi - 5pi/6)= 7pi/6
Answer: 5 pi/6 and 7 pi/6
Answer:
Got my points deducted by a loser name PoeticAesthetics
Step-by-step explanation:
Step-by-step explanation:
g(n-7) = (n-7) ^2-6/7 (n-7) = n^2 -14n+49-6/7 n +6= n^2-104/7 n +55
Hi student, let me help you out! :)
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We are asked to find the slope of this graph; we are provided with two points:



- What we need in order to find the slope are two points and the slope formula.
Here's the formula:

Where
y2 and y1 are y-coordinates
x2 and x1 are x-coordinates
Substitute the values:

Simplify!

Simplify more!

Hope it helps you out! :D
Ask in comments if any queries arise.
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~Just a smiley person helping fellow students :)
Answer:
The hypotenuse is square root of 65
Step-by-step explanation:
a^2 + b^2 = c^2
legs of the right triangle are a and b. Just substitute 4 for a and 7 for b and solve.
4^2+7^2=16+49=65
c^2=65
Find the square root of both sides to get
c=the square root of 65