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nekit [7.7K]
2 years ago
9

What is the area, in square feet, of the trapezoid below?

Mathematics
1 answer:
PtichkaEL [24]2 years ago
8 0

Answer:  " 94. 6  ft² ".
_____________________

<u>Step-by-step explanation</u>:

The formula for the area of a trapezoid:
______________________
A = (1/2) * (b1 + b2) * (perpendicular height, "h" ) ;

      in which:
______________________
 "A = area (in units of ft²) "

 "b1 = length of (base one) = 7.7 ft (from diagram) ;  

 "b2 = length of (base two—the other base) = 14.3 ft. ;
 "h = height (perpendicular) = 8.6 ft.
_______________________

To solve for the Area, "A" ; we plug in the known values:
_______________________
A = (1/2) * (b1 + b2) * (perpendicular height, "h" );

   =  (1/2) * (7.7 ft + 14.3 ft) * (8.6 ft) ;

  = (1/2) * (22 ft.) * (8.6 ft) ;

  = (11 ft.) * (8.6 ft.) ;

   = (11) * (8.6) * (ft.) * (ft.) ;

   = (11) * (8.6) * ft² ;

A  =   " 94. 6  ft² ".

_______________________
Hope this is helpful to you!
  Best wishes!
________________________

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Note: Let us consider, we need to find the m\angle ABC and m\angle DBC.

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In the given figure, BD is the angle bisector of ABC.

To find:

The m\angle ABC and m\angle DBC.

Solution:

BD is the angle bisector of ABC. So,

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Now,

m\angle DBC=(x+20)^\circ

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