All categories

3 years ago

Evaluate the function Find f(2) f(2) =

Mathematics

1 answer:

earnstyle [38]3 years ago

7 0

F(2) is the x value, so you need to look at where the line is in the y direction at x = 2

The black dot on the graph is at x = 2 and is at y = 4

Answer: f(2) = 4

You might be interested in

Mark's soup recipe makes 6 servings and uses 4 carrots and 2 potatoes. Drag carrots and potatoes into the box to show how many M

Vitek1552 [10]

The answer would be 27

7 0

4 years ago

Read 2 more answers

Divide write the answer in simplest form

Rom4ik [11]

Answer:

3 is the answer

1/3*9/1=9/3=3

Step-by-step explanation:

6 0

2 years ago

I need help with this

Trava [24]

Answer:

https://www.mathpapa.com/algebra-calculator.html

Step-by-step explanation:

4 0

3 years ago

Describe how you could find the product of 700 and 900

gizmo_the_mogwai [7]

7 * 9 = 63
add four 0's from 700 and 900
630,000

6 0

4 years ago

Prove that<br>{(tanθ+sinθ)^2-(tanθ-sinθ)^2}^2 =16(tanθ+sinθ)(tanθ-sinθ)

USPshnik [31]

First, expand the terms inside the bracket you will get

$(( \tan {}^{2} (x) + 2 \tan(x) \sin(x) + \sin {}^{2} (x) - ( \tan {}^{2} (x) - 2 \tan(x) + \sin {}^{2} (x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$( 4 \tan(x) \sin(x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16 \tan {}^{2} (x) \sin {}^{2} (x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16 \tan {}^{2} (x) (1 - \cos {}^{2} (x) ) = 16 (\tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16( \tan {}^{2} (x) - \frac{ \sin {}^{2} (x) \cos {}^{2} ( {x}^{} ) }{ \cos {}^{2} (x) }$

$16( \tan {}^{2} (x) - \sin {}^{2} (x) ) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

5 0

2 years ago