Answer:
It will take <u><em>80 days</em></u> for the bull calf to reach a weight of 500 kilograms.
Step-by-step explanation:
Given:
The weight of a bull calf is 388 kilograms.
Now, to find the weight of bull calf of how long it will take to reach a weight of 500 kilograms, if it’s weight increases at a rate of 1 2/5 kilograms per day.
Required weight which to be increased = 500 - 388 = 112 kilograms.
Rate of weight increase = 
= 
Thus, the time required = 
= 
= 
<em>The time required = 80 days</em>.
Therefore, it will take 80 days for the bull calf to reach a weight of 500 kilograms.
To determine the number of those who joined the basketball camp this year, we just have to multiply the number of those who joined last year by the decimal equivalent of the percentage given. That is,
x = 88(1.25)
x = 110
Therefore, there are a total of 110 players for this years basketball camp.
Answer:
(IQR) interquartile range = 5
Step-by-step explanation:
Lower quartile: 48
Upper quartile: 53
Median: 52
Lowest value: 46
Highest value: 55
(IQR) interquartile range: Upper quartile - Lower quartile = final answer
(IQR) interquartile range: 53 - 48 = 5
- Diameter of cylinder is <u>1</u><u>4</u><u> </u><u>units.</u>
<h3><u>Explamation </u><u>:</u></h3>
<em><u>Given </u></em><em><u>:</u></em><em><u>-</u></em>
- Volume of cylinder = 245π cubic units
- Height of cylinder = 5 units
<em><u>To </u></em><em><u>Find </u></em><em><u>:</u></em><em><u>-</u></em>
<em><u>Solution </u></em><em><u>:</u></em><em><u>-</u></em>
<em>Firstly </em><em>lets </em><em>calculate </em><em>radius </em><em>of </em><em>cylinder </em><em>by </em><em>using </em><em>formula </em><em>of </em><em>volume </em><em>of </em><em>cylinder,</em><em> </em><em>as </em><em>we </em><em>know </em><em>that;</em>
- Volume of cylinder = πr²h
<em>Putting </em><em>all </em><em>values </em><em>we </em><em>get;</em>
➸ 245π = π × r² × 5
<em>By </em><em>cutting </em><em>'π' </em><em>with </em><em>'π' </em><em>we </em><em>get;</em>
➸ 245 = r² × 5
➸ 245/5 = r²
➸ 49 = r²
➸ √(49) = r²
➸ √(<u>7</u><u> </u><u>×</u><u> </u><u>7</u><u>)</u> = r²
➸ 7 = r
➸ r = 7 units
- <u>Hence,</u><u> </u><u>radius </u><u>of </u><u>cylinder </u><u>is </u><u>7</u><u> </u><u>units.</u>
<em>Now </em><em>lets </em><em>calculate </em><em>its </em><em>diameter,</em><em> </em><em>as </em><em>we </em><em>know </em><em>that;</em>
<em>Putting </em><em>all </em><em>values </em><em>we </em><em>get;</em>
➸ Diameter = 7 × 2
➸ Diameter = 14 units
- <u>Hence,</u><u> </u><u>diameter </u><u>of </u><u>cylinder </u><u>is </u><u>1</u><u>4</u><u> </u><u>units.</u>
The solution to 6×+2y=6 is y=0.5
The solution for 7×+3y=5 is y
= 0.238095 (.238095 is repeated)
