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3 years ago

The two cones below are similar. What is the height of the smaller cone?

Mathematics

2 answers:

Ugo [173]3 years ago

6 0

Given that the two cone are similar, then
3/7 = x/5
7x = 15
x = 15/7

Eddi Din [679]3 years ago

5 0

Answer: The correct option is (D) $\dfrac{15}{7}.$

Step-by-step explanation: Given that the two cones in the figure are similar.

We are to find the height 'x' of the smaller cone.

The height and radius of the bigger cone are 5 units and 7 units respectively.

The radius of the smaller cone is 3 units.

Since the two cones are similar, so their corresponding heights and radius will be proportional.

Therefore, we must have

$\dfrac{5}{x}=\dfrac{7}{3}\\\\\\\Rightarrow 5\times 3=7x\\\\\\\Rightarrow7x=15\\\\\\\Rightarrow x=\dfrac{15}{7}.$

Thus, the height of the smaller cone is $\dfrac{15}{7}~\textup{units}.$

Option (D) is correct.

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it takes approximately 1200 KG of coal to produce the energy needed to make 1 kg of aluminum is a single soda can requires 15 g

Pavel [41]

see so,1200 kg of coal=1kg of aluminum

if 1 soda can needs 15g of aliminium so

1200/15=80kg coal will be needed for 1 can of soda.

4 0

3 years ago

Pleeeeeeeeaaaseeeeee help meeeeeeee!!!!!!!!!

zaharov [31]

Answer:

Option D.

$A =96\pi\ cm^2$

Step-by-step explanation:

The area of the circular bases is:

$A_c = 2\pi(a) ^ 2$

Where

$a=4\ cm$ is the radius of the circle

Then

$A = 2\pi(4) ^ 2$

$A = 32\pi\ cm^2$

The area of the rectangle is:

$A_r=b * 2\pi r$

Where

$b=8\ cm$

b is the width of the rectangle and $2\pi r$ is the length

Then the area of the rectangle is:

$A_r=8 * 2\pi (4)$

$A_r=64\pi\ cm^2$

Finally the total area is:

$A = A_c + A_r\\\\A = 32\pi\ cm^2 + 64\pi\ cm^2\\\\$

$A =96\pi\ cm^2$

7 0

4 years ago

Read 2 more answers

The height "h" of a ball thrown straight up with a velocity of 88 ft/s is given by h = -16t^2 + 88t where "t" is the time it is

Dvinal [7]

By definition of the zeros of ta quadratic function, for 5.5 seconds the ball is in the air before it hits the ground.

<h3>Zeros of a function</h3>

The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.

That is, the zeros represent the roots of the polynomial equation that is obtained by making f(x)=0.

In summary, the roots or zeros of the quadratic function are those values of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.

<h3>Time the ball is in the air before it hits the ground</h3>

In this case, the height "h" of a ball thrown straight up with a velocity of 88 ft/s is given by h = -16t² + 88t, where "t" is the time it is in the air.

When the ball hits he ground, he height h has a value of zero. This is h=0. Replacing in the previous expression for the height you get:

0= -16t² + 88t

It can be solved by extracting the term "t" as a common factor:

0= t×(-16t + 88)

The Zero Product Principle says that if the product of two numbers is 0, then at least one of the factors is 0. Then:

t= 0

0= -16t + 88

Solving: -88= -16t

(-88)÷ (-16)=t

Finally, this means that for 5.5 seconds the ball is in the air before it hits the ground.

Learn more about the zeros of a quadratic function:

brainly.com/question/12649112