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saw5 [17]
3 years ago
10

Nitrogen-fixing bacteria change a nitrogen molecule into a form of nitrogen that plants can use. The nitrogen enters the plant t

hrough its root system and is used to build new plant tissue. What will most likely happen to the nitrogen next?
Biology
1 answer:
forsale [732]3 years ago
6 0
The nitrogen is passed through the food chain by animals that consume the plants, and then released into the soil by decomposer bacteria when they die.
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Vascular tissues main function is
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Answer:

The vascular tissues include xylem, which conducts water and minerals from the roots upward and throughout the plant, and phloem, which transports dissolved nutrients in all directions within the plant. The main conducting vessels of xylem are the tracheids and the vessels.

hope this helps you out

Explanation:

i had a medical class last month and i know this stuff

5 0
4 years ago
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In gymnosperms, the seed coat develops from the integument. in angiosperms, the seed coat develops from the __________.
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<span>In gymnosperms, the seed coat develops from the integument. in angiosperms, the seed coat develops from the </span>integuments.
3 0
3 years ago
Cystic fibrosis is an autosomal recessive disorder. In one population, the frequency of affected individuals (A 2 A 2) is 0.0004
Simora [160]

Hardy Weinberg Equilibrium

Explanation:

  • Hardy Weinberg Equilibrium formula for allelic frequency is: p+q=1
  • Hardy Weinberg Equilibrium formula for genotypic frequency is: p^2+q^2+2pq=1
  • Here,p=frequency of dominant allele

                 q=frequency of recessive allele

                 p^2=frequency of dominant genotype

                 q^2=frequency of recessive genotype

                 2pq=frequency of heterozygous genotype

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here,affected individuals means the one's having Cystic Fibrosis and since it is recessive disease so we can write frequency of recessive genotype as:     q^2=0.0004

  • If q^2=0.0004 q will be 0.02;frequency of recessive allele will be 0.02
  • Using the formula p+q=1

                                       p+0.02=1\\p=1-0.02=0.98

  • hence,frequency of dominant allele will be 0.98
  • Frequency of dominant genotype will be p^2=(0.98)^2=0.9604
  • Frequency of heterozygous genotype will be 2pq=2*0.98*0.02=0.0392

7 0
4 years ago
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</span><span>c. it is the respone to a stimulus</span>
8 0
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Order the steps for starting a garden
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