All categories

3 years ago

Plz help 20 points and more

Mathematics

2 answers:

tino4ka555 [31]3 years ago

8 0

I believe the answer is c and have a very nice day

Lilit [14]3 years ago

3 0

The answer is C
By multiplying -65 and 8, you get -520
And I'm pretty sure there is no need to eliminate in this equation

You might be interested in

On Tuesday, Hayley only has 15 cups of flour and 9 eggs, but she has more than enough butter and sugar. Which system of linear i

BabaBlast [244]

Missing part of the question

Hayley bakes zucchini bread and banana bread. Some ingredients Hayley uses for each type of bread are shown in the tables

Zucchini Bread

2 eggs 2 cups of flour 1.5 cups of sugar 0.5 stick of butter

Banana Bread

1 egg 3 cups of flour 2 cups of sugar 0.25 stick of butter

Answer:

$2z + b \le 9$

$2z + 3b \le 15$

Step-by-step explanation:

Given

$Flour = 15$

$Egg =9$

Since there are enough of other ingredients, we will only consider the amount of eggs and cups of flour.

So, we have:

Zucchini Bread

$Egg = 2$

$Flour = 2$

Banana Bread

$Egg = 1$

$Flour = 3$

For the eggs

The ratio of eggs to use in the Zucchini bread to Banana bread is:

$Egg = 2$ (z) : $Egg = 1$ (b)

This gives:

$2z + 1b$

The total number of eggs cannot exceed 9.

So, the inequality is:

$2z + 1b \le 9$

$2z + b \le 9$

For the flours

The ratio of flours to use in the Zucchini bread to Banana bread is:

$Flour = 2$ (z) : $Flour = 3$ (b)

This gives:

$2z + 3b$

The total cups of flours cannot exceed 15.

So, the inequality is:

$2z + 3b \le 15$

Hence:

The system of inequalities is:

$2z + b \le 9$

$2z + 3b \le 15$

7 0

2 years ago

Help !! Is the work shown in the simplification below correct? Explain.

melomori [17]

Try this solution:
1. rules:
$cosec(t)= \frac{1}{sin(t)} ; \ sec(t)= \frac{1}{cos(t)} .$
2. according to the rule described above:
$\frac{cosec(t)}{sec(t)}= \frac{1}{sin(t)}: \frac{1}{cos(t)}= \frac{1}{sin(t)}* \frac{cos(t)}{1} = \frac{cos(t)}{sin(t)}=cotang(t).$

6 0

2 years ago

Read 2 more answers

Use cylindrical coordinates. find the volume of the solid that is enclosed by the cone z = x2 + y2 and the sphere x2 + y2 + z2 =

sashaice [31]

Let $R$ be the solid. Then the volume is

$\displaystyle\iiint_R\mathrm dV=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=\sqrt8}\int_{\zeta=r^2}^{\zeta=\sqrt{72-r^2}}r\,\mathrm d\zeta\,\mathrm dr\,\mathrm d\theta$

which follows from the facts that

$\begin{cases}x=r\cos\theta\\y=r\sin\theta\\z=\zeta\end{cases}\implies\mathrm dx\,\mathrm dy\,\mathrm dz=r\,\mathrm dr\,\mathrm d\theta\,\mathrm d\zeta$
(by computing the Jacobian)

and

$z=x^2+y^2=r^2\implies z+z^2=72\implies z=-9\text{ or }z=8$
(we take the positive solution, since it's clear that $R$ lies above the $x$ - $y$ plane)
$r^2+z^2=72\implies z=\pm\sqrt{72-r^2}$
(again, taking the positive root for the same reason)
$z=r^2\implies 8=r^2\implies r=\sqrt8$

$\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=\sqrt8}\int_{\zeta=r^2}^{\zeta=\sqrt{72-r^2}}r\,\mathrm d\zeta\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle2\pi\int_{r=0}^{r=\sqrt8}\int_{\zeta=r^2}^{\zeta=\sqrt{72-r^2}}r\,\mathrm d\zeta\,\mathrm dr$
$=\displaystyle2\pi\int_{r=0}^{r=\sqrt8}r(\sqrt{72-r^2}-r^2)\,\mathrm dr$
$=\displaystyle2\pi\int_{r=0}^{r=\sqrt8}(r\sqrt{72-r^2}-r^3)\,\mathrm dr$
$=\dfrac{32(27\sqrt2-35)\pi}3$