Answer:
k can either be
12
or
−
12
.
Step-by-step explanation:
Consider the equation
0=x2+4x+4
. We can solve this by factoring as a perfect square trinomial, so
0=(x+2)2→x=−2 and−2
. Hence, there will be two identical solutions.
The discriminant of the quadratic equation (b2−4ac) can be used to determine the number and the type of solutions. Since a quadratic equations roots are in fact its x intercepts, and a perfect square trinomial will have
2 equal, or 1
distinct solution, the vertex lies on the x axis. We can set the discriminant to 0 and solve:
k2−(4×1×36)=0
k2−144=0
(k+12)(k−12)=0
k=±12
Therefore the answer is D. (x + 1)(x2 + 2)
Y = mx + b
slope(m) = -2/3
(2,-5)...x = 2 and y = -5
now we sub, we r looking for b, the y int
-5 = -2/3(2) + b
-5 = - 4/3 + b
-5 + 4/3 = b
- 15/3 + 4/3 = b
- 11/3 = b
equation is : y = -2/3x - 11/3...but we need it in standard form
Ax + By = C
y = -2/3x - 11/3
2/3x + y = - 11/3....multiply by 3
2x + 3y = -11 <== standard form
Answer:
x= 20 i think sorry if it's wrong⊙﹏⊙
Answer:
h(0)= -7
Step-by-step explanation:
that is my answer