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N76 [4]
3 years ago
11

Two pounds of peaches cost $4.20. How much will five pounds cost?

Mathematics
2 answers:
Dimas [21]3 years ago
8 0
Set up multiplication of ratios so that they cancel out units that you do not need in your final answer...

5lb($4.20/2lb)=$10.50
klasskru [66]3 years ago
5 0
<span>2 pounds of peaches cost $4.20
</span>5 pounds of peaches cost $??

5 x 4.20 / 2 = 10.5

answer

<span>five pounds will cost  $10.50</span>
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0.002 is 1/100 of what decimal?
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What are the minimum, first quartile, median, third quartile, and maximum of the data set? PLEASE Show your work.
Schach [20]
54 55 59 61 61 62 68 70 72
First put your numbers in order from least to greatest. This shows your minimum is 54 and maximum is 72.
In the middle of the data set is 61.

54 55 59 61. 61. 62 68 70 72

To find the first qaurtile only use the numbers before rhe median (54 55 59 61) and find the median of that. Since 55 and 59 are both in the middle add them both and divide by two to find the middle lf those two numbers. You should get 57. So 57 is the first quartile.

Do the same steps with the numbers after the meadian for your third quartile. You should get 69 as your answer for the third quartile.
7 0
3 years ago
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Each of the performers at a circus convention is either a unicyclist, a mime or an aerial artist. The ratio of unicyclists to mi
Alexeev081 [22]

Answer:

14.52% are unicyclists

Step-by-step explanation:

First, we can use proportions to find the number of unicyclists at the convention. Since we know that the ratio of unicyclists to aerial artists is 9:11, and there are 88 aerial artists, we can set up the following equation:

\frac{9}{11}=\frac{x}{88}

If we cross multiply, we get that 11x = (88)(9). After we divide through by 11 to isolate x, we get that x = (8)(9) = 72

Second, we have to figure out the number of mimes at the convention to figure out the total number of people there. We know that the ratio of unicyclists to mimes is 3:14, and the number of unicyclists is 72. So, we can set up the following proportion:

\frac{3}{14}=\frac{72}{y}

If we cross multiply, we get that 3y = 1008, or y = 336 mimes

The total number of people at the convention is 336 mimes + 72 unicyclists + 88 unicyclists = 496. Now we have to figure out what percent of 496 is 72 (the number of unicyclists). If we let z = the percentage, we can simply set up an equation that says that 72 is z% of 496:

72=0.01z*496\\0.01z=0.14516\\z=14.52

This means that approximately 14.52% of the performers are unicyclists.

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2 years ago
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