Find the value of p. p − 1 = 5 p + 3p − 8
2 answers:
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We first need to determine whether we are dealing with means or proportions in this problem. Since we are given the sample and population mean, we know that we are dealing with means.
Since we have one sample mean, this means we are creating a confidence interval for one sample (1 Samp T Int).
Normally we would check for conditions, but since this is not formulated as a "real-world scenario" type problem, it is hard to check for randomness and independence. Therefore, I will be excluding conditions from this answer.
<h3>Confidence Interval Formula</h3>The formula for constructing a <u>confidence interval for means</u> is as follows:
We are given these variables:
Plug these values into the formula for the confidence interval:
In order to find t*, we can use this formula:
Calculating the z-score associated with "A" will give us t*.
So, let's plug in the confidence interval 95% (.95) into the formula:
Use your calculator or a t-table to find the z-score associated with this area under the curve.. you should get:
Now, let's finish the confidence interval we created:
We can calculate the confidence interval, using this formula, to be:
We are 95% confident that the true population mean μ lies between <u>47.4697 and 52.5303</u>.
In the given equation, as the value of <em>y</em> increase, the value of <em>x</em> also
increases.
- Yes, 4·y = 16·x is a direct variation
Reasons:
A direct variation is a relationship that exists between two variables. It is
also known as a direct proportion which can be expressed as; y = k·x
Where <em>k</em> is a number
The given equation is 4·y = 16·x
Dividing both sides by 4 gives;
Which gives;
y = 4·x
Comparing the above equation with the equation for a direct variation gives;
y = 4·x
y = k·x
Therefore;
k = 4
The equation, y = 4·x, and therefore, the equation from which it is derived, 4·y = 16·x, is a direct variation.
Learn more about direct variation here: