Answer:
4032 integers.
Step-by-step explanation:
Lest start with -2016. There are 2016 integers from -2016 to 0. Then we see how many integers are from 0 to 2016. there are 2016. If you add them up, you get 4032.
Answer:
$196
Step-by-step explanation:
Lets assume,
cost of a belt = 'x'
cost of a pair of pants = 'y'
Now, According to the question;
- x + y = 490;
- cost of a bag = twice the cost of belt = 2x;
- cost of a pair of pants = twice the cost of bag
⇒ y = 2×2x ⇔ 4x
hence, by subtituting the values in equation' we get;
⇒ x + 4x = 490
⇒ 5x = 490
⇒ x = 98
So, the difference between the cost of the pair of pants and the bag ;
⇒ y - 2x
⇒ 4x - 2x
⇒ 2x = 2×98 = 196.
Question #25:
One way to solve this is by multiplying the number of packages per serving by the number of guests.
1/4 * 16 = 4 packages to serve 16 guests. This means he doesn't have enough.
A second way to solve this is by diving the number of packages by the number of packages it takes to make on serving.
3 1/2 ÷ 1/4 = 14 guests he can serve. This means he doesn't have enough.
Question #26:
First, find common denominators.
2/3 = 8/12
1/4 = 3/12
Second, subtract.
8/12 - 3/12 = 5/12
Therefore, the tank is 5/12 full at the end of the trip.
Question #27:
1/2 is cut off then 1/3 is cut off. This means 3/6 was cut off to bundle newspapers, then 1/6 was cut off to make parcel. In all, 4/6 was cut off the original string. Afterwards, 2/6 was left over. So, just multiply; 2 * 3 = 6.
Therefore, the original string was as a total of 6 meters.
Best of Luck!
The function would be h = 270 - 2.5s, where h is the height (in feet) and s it the time (in seconds) that has passed.
The 270 represents the initial value, which is given. We are told that the initial height of the block is 270 feet.
2.5s represents the feet that it has descended. We know the block is lowered at a rate of 2.5 feet per second. Multiplying this by s, the time, will give us how much it has descended.
Answer:
I think it's A and D
Step-by-step explanation:
I just decided the denominator and numerator.
