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bogdanovich [222]

2 years ago

13

At a high school the student government is made up of 5 seniors, 4 juniors, 3 sophomores and 2 freshmen. If there are 8 seniors,

9 juniors, 12 sophomores and 7 freshmen running, in how many ways can the student government be selected?

1 answer:

hjlf2 years ago

5 0

Answer:

32598720

Step-by-step explanation:

<u>Combination for the school government requires:</u>

5 out of 8 seniors = 8! / 3!5! = 6*7*8/2*3 = 7*8 = 56
4 out of 9 juniors = 9! / 4!5! = 6*7*8*9/2*3*4= 7*2*9 = 126
3 out of 12 sophomores = 12! / 3!9! = 10*11*12/2*3 = 10*11*2 = 220
2 out of 7 fishermen = 7! / 2!5! = 6*7/2 = 21

<u>So number of total ways is:</u>

56*126*220*21 = 32598720

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Murrr4er [49]

Answer:

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tigry1 [53]

Answer:

a) The 98% confidence interval would be given (0.182;0.218).

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Step-by-step explanation:

Data given and notation

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$\hat p=0.2$ estimated proportion of England people who are deficient in Vitamin D

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Confidence =0.98 or 98%

z would represent the statistic (variable of interest)

p= population proportion of England people who are deficient in Vitamin D

Part a

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 98% confidence interval the value of $\alpha=1-0.98=0.02$ and $\alpha/2=0.01$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.33$

And replacing into the confidence interval formula we got:

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$0.20 + 2.33 \sqrt{\frac{0.2(1-0.2)}{2700}}=0.218$

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Part b

We are 98% confident that the true proportion of of England people who are deficient in Vitamin D is between 0.182 and 0.218.

Part c

If repeated samples were taken and the 98% confidence interval computed for each sample, 98% of the intervals would contain the population proportion.

Part d

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igor_vitrenko [27]

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2 years ago

Type your answer and then click or tap Done.

masya89 [10]

Answer:

See below

Step-by-step explanation:

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Step by step solution :

Step 1 :

Equation at the end of step 1 :

x • (x - 2y) - (y - x)2

Step 2 :

2.1 Evaluate : (y-x)2 = y2-2xy+x2

Final result :

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