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Fofino [41]
4 years ago
9

2. Two chemical bonds unite three atoms into a molecule. Which types of bonds are

Chemistry
2 answers:
Radda [10]4 years ago
8 0

Answer : The correct option is, (B) two covalent bonds

Explanation :

Ionic bond : It is defined as the bond that is formed by complete transfer of electrons from one atom to another atom.

That means, the atom which looses the electron is known as electropositive atom and the atom which gains the electron is known as electronegative atom.

The ionic bond is usually formed between a metal and a non-metal.

Covalent bond : It is defined as the bond which is formed when sharing of electrons takes place between the atoms.

This is usually formed between two non-metals.

Metallic bond : It is defined as the bond that is formed from the electrostatic attraction between the free electrons and positively charged metal ions.

As per question, the two chemical bonds unite three atoms into a molecule, it is formed by the covalent bond.

For example : H_2O is formed by the combination of 2 hydrogen and 1 oxygen atom by the two covalent bonds because hydrogen and oxygen is a non-metal element.

Hence, the correct option is, (B) two covalent bonds

Alex777 [14]4 years ago
5 0
B. Two covalent bonds.
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Which sublevels are full when an atom has a noble gas configuration?
NemiM [27]
<h3>Answer:</h3>

s-sub-level and p-sub-level

<h3>Explanation:</h3>
  • Group 18 elements in the periodic table are known as noble gases.
  • They have an octet configuration with their outermost s and p-sub-levels full, which makes them inert or nonreactive.
  • The s-sub-level takes up a maximum of 2 electrons while the p-sub-level holds a maximum of 6 electrons.
  • They include, argon, neon, xenon, krypton, etc.
  • Their electron configuration shows full outermost s and p-sub-levels.
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3 years ago
True or false: Gravity plays an important role in the formation of stars.
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8 0
3 years ago
Calculate the Ka for a 0.3 M solution of HA (unknown weak acid) if the pH = 3.65. The reaction can be modelled as HA (aq) + H2O
Levart [38]

The Ka : 1.671 x 10⁻⁷

<h3>Further explanation</h3>

Given

Reaction

HA (aq) + H2O (l) ←→ A- (aq) + H3O+ (aq).

0.3 M HA

pH = 3.65

Required

Ka

Solution

pH = - log [H3O+]

\tt [H_3O^+]=10^{-3.65}=2.239\times 10^{-4}

ICE method :

HA (aq)        ←→   A- (aq)    +    H3O+ (aq).

0.3                           0                 0

2.239.10⁻⁴           2.239.10⁻⁴   2.239.10⁻⁴

0.3-2.239.10⁻⁴    2.239.10⁻⁴    2.239.10⁻⁴

\tt Ka=\dfrac{[H_3O^+][A^-]}{[HA]}\\\\Ka=\dfrac{(2.239.10^{-4}){^2}}{0.3-2.239.10^{-4}}\\\\Ka=1.671\times 10^{-7}

5 0
3 years ago
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