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2 years ago

What are 5 of the critical events in evolution that occurred in the Paleozoic era?!!

Chemistry

1 answer:

soldi70 [24.7K]2 years ago

5 0

Answer:

Cambrian, Ordovician, Silurian, Devonian, Carboniferous, and Permian

Explanation:

These all occurred in the paleozoic Era I hope you do great good luck <3

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Solid iron metal reacts with solid sulfur at room temperature to produce solid iron (ll) sulfide? Express as a chemical equation

kupik [55]

Answer:Fe+S=FeS

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5 0

3 years ago

Warm air _____.

svp [43]

Answer:

cools as it rises, then sinks back down

Explanation:

The movement of air is a convection current. Convection currents occur when warm air rises, cools down, and sinks due to gained density, replacing the warm air closer to the ground, creating a cycle.

5 0

3 years ago

6. Why does the sun seem to change position in the sky?

Dafna11 [192]

A. Earth’s Rotation

4 0

3 years ago

The decomposition of N_2O_5(g) following 1st order kinetics. N_2O_5(g) to N_2O_4(g) + ½ O_2(g) If 2.56 mg of N_2O_5 is initially

Crank

Answer: The rate constant is $0.334s^{-1}$

Explanation ;

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = ?

t = age of sample = 4.26 min

a = initial amount of the reactant = 2.56 mg

a - x = amount left after decay process = 2.50 mg

Now put all the given values in above equation to calculate the rate constant ,we get

$4.26=\frac{2.303}{k}\log\frac{2.56}{2.50}$

$k=\frac{2.303}{4.26}\log\frac{2.56}{2.50}$

$k=5.57\times 10^{-3}min^{-1}=5.57\times 10^{-3}\times 60s^{-1}=0.334s^{-1}$

Thus rate constant is [tex]0.334s^{-1}

4 0

3 years ago

The town of Natrium, West Virginia, derives its name from the sodium produced in the electrolysis of molten sodium chloride (NaC

Alona [7]

Explanation:

The reaction equation will be as follows.

$Na^{+} + e^{-} \rightarrow Na(s)$

Hence, moles of Na = moles of electron used

Therefore, calculate the number of moles of sodium as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{4500 g}{23 g/mol}$ (as 1 kg = 1000 g)

= 195.65 mol

As, Q = $n \times F$ where F = Faraday's constant

= $195.65 mol \times 96500 C$

= $1.88 \times 10^{7}$ mol C

Relation between electrical energy and Q is as follows.

E = $Q \times V$

Hence, putting the given values into the above formula and then calculate the value of electricity as follows.

E = $Q \times V$

= $1.88 \times 10^{7} \times 5$

= $9.4 \times 10^{7} J$

As 1 J = $2.77 \times 10^{-7}$ kWh

Hence, $\frac{9.4 \times 10^{7}}{2.77 \times 10^{-7}}$ kWh

= 3.39 kWh

Thus, we can conclude that 3.39 kilowatt-hours of electricity is required in the given situation.

7 0

4 years ago

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