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3 years ago

If c= 8 what is the value of 4c + ( 4-3) Also, if t= 5, what is the value of 16-3t?

2 answers:

8 0

Hope this is the brainliest answer and hope this helped you learn★

ANSWER:

1st one- 33
2nd one- 1

STEP BY STEP:

First let's rewrite the equation

4c + (4-3)

Now the paper told us that c=8. So let's take out the letter c in the equation and substitute it for its value.

4(8) + (4-3)

Now we solve using PEMDAS. We start with the parentheses which is (4-3).

4(8) + 1

Now lets go down to multiplication. 4(8)

32 + 1

That is our final answer for #1. 33.

_________________________________

Now let's move on to equation #2. Let's rewrite the equation.

16 - 3t

Just as we did before, we can substitute t for the given value. In this case, 5.

16 - 3(5)

For the next step we move on to multiplication. Let's multiply 3(5)

16 - 15

Now we have a simple subtraction problem to give us our answer! The answer for #2 is now 1.

lions [1.4K]3 years ago

6 0

The first answer is 33.
And secomd one is 1.

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3 years ago

The second term of a GP is 4, the fifth term is 81. Find the seventh term

navik [9.2K]

Answer:

The seventh term of a G.P is

$t_{7} = 33,097.211$

Step-by-step explanation:

step(i):-

Given the second term of a G.P is '4'

The general term of nth term is

$t_{n} = ar^{n-1}$

$t_{4} = ar^{4-1} =4$

$ar^{3} =4$ …(i)

Also Given the fifth term of a G.P is '81'

$t_{5} = ar^{5-1} =81$

$ar^{4} =81$ …(ii)

Step(ii):-

Dividing the equation (ii) divided by (i)

$\frac{ar^{4} }{ar^{3} } = \frac{81}{4}$

cancellation ' a' and 'r' terms , we get

$r = \frac{81}{4}=20.25$

substituting 'r' Value in equation (i), we get

$ar^{3} =4$

$a(\frac{81}{4}) ^{3} =4$

$a = \frac{4X4X4X4}{(81)^{3} }= \frac{256}{531,441}$

a = 0.00048

Step(iii):-

The seventh term of G.P

The general term of nth term is

$t_{n} = ar^{n-1}$

$t_{7} = (0.00048)(20.25)^{7-1}$

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Step-by-step explanation:

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Answer:

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4 years ago

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