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2 years ago

please find the area

Mathematics

1 answer:

Eddi Din [679]2 years ago

8 0

Answer: 6.72 yd^2

Step-by-step explanation:

The area of a triangle is equal to the base * height/2.

Therefore, the area = 3.2*4.2/2 yd^2

Area = 6.72 yd^2

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Given that the equation y=mx + b where m is 12 and the line passes through the point (-2,8), what would be the value of b?

larisa86 [58]

Answer:

Step-by-step explanation:

The answer would be D. We can continue the line from the point (-2,8) because we know the slope so we will continue it forward by two on the x axis. Since we go forward by two we are going up by 24 (12*2) on the y axis so the y intercept (b) would be 8 + 24 which is 32. Sorry if it is hard to understand.

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3 years ago

Solve for w. 8= 4 + w

Yuri [45]

W=4 that the answer !!!!!

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3 years ago

Plz help me!!!!!!!!!

Over [174]

Answer: $\bold{\dfrac{4\pm \sqrt{6}}{2}}$

Step-by-step explanation:

$\dfrac{3}{y-2}-2=\dfrac{1}{y-1}\\\\\\\text{Multiply by the LCD (y-2)(y-1) to clear the denominator:}\\\\\dfrac{3}{y-2}(y-2)(y-1)-2(y-2)(y-1)=\dfrac{1}{y-1}(y-2)(y-1)\\\\\\3(y-1)-2(y-2)(y-1)=1(y-2)\\\\3y-3-2(y^2-3y+2)=y-2\\\\3y-3-2y^2+6y-4=y-2\\\\-2y^2+9y-7=y-2\\\\0=2y^2-8y+5\quad \rightarrow \quad a=2,\ b=-8,\ c=5\\\\\\\text{Quadratic formula is: }x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(-8)\pm \sqrt{(-8)^2-4(2)(5)}}{2(2)}\\\\\\.\ =\dfrac{8\pm \sqrt{64-40}}{2(2)}$

$.\ =\dfrac{8\pm \sqrt{24}}{2(2)}\\\\\\.\ =\dfrac{8\pm 2\sqrt{6}}{2(2)}\\\\\\.\ =\dfrac{4\pm \sqrt{6}}{2}$

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3 years ago

Which one is the right one

olganol [36]

Answer:

Step-by-step explanation:

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3 years ago

Trapezoid.mp4 Find the value of x and y. Rek2 20 x 12 Y x = y =

algol13

9514 1404 393

Answer:

x = 12
y = 20

Step-by-step explanation:

The figure only makes sense as a kite, in which case left sides are equal and right sides are equal.

x = 12

y = 20

6 0

2 years ago

￼please find the area

please find the area