La respuesta es 112, es una regla de tres simples
The distribution shaped for which the mean and median must be about the same will be:
D. Symmetric
E. uniform
<h3>How to illustrate the information?</h3>
In a symmetric distribution, the median is equal to the mean. The bell-shaped distribution is same as the standard normal distribution.
In a right-skewed distribution, the median is much less than the mean and a bimodal distribution is one with two modes.
Therefore, the correct options are D and E.
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=0 just need points tho lol
There are 210 different possible combinations
<h3>How to determine the number of possible combinations?</h3>
The given parameters are:
- Types of candy, n = 10
- Candies to taste, r = 6
The number of possible combinations is calculated using:
Combination = nCr
This gives
Combination = 10C6
Apply the combination formula
Combination = (10!)/((10 - 6)!6!)
Evaluate
Combination = 210
Hence, there are 210 different possible combinations
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We are given : m∠WYX=(2x−1)° and m∠WYZ=(4x+1)°.
∠WYX and ∠WYZ are complementary.
We know, sum of complementary angles is = 90°.
So, we need to add ∠WYX and ∠WYZ and set it equal to 90°.
m∠WYX + m∠WYZ = 90°.
Plugging values of ∠WYX and ∠WYZ in the above equation, we get
(2x−1)° + (4x+1)° = 90°.
Removing parentheses from both sides,
2x-1 + 4x+1 =90.
Combining like terms,
2x+4x= 6x and -1+1 =0
6x +0 =90.
6x=90.
Dividing both sides by 6.
6x/6 =90/6
x= 15.
Plugging value of x=15.
m∠WYX=(2x−1)° = 2*15 -1 = 30 -1 =29
m∠WYZ=(4x+1)° = 4*15 +1 = 60+1 = 61.
Therefore, ∠WYX=29° and ∠WYZ=61°.
