HELP ASAP with this question.

A train left isiolo on Friday at 11:45 pm.it took 8 hrs 55 mins to reach Nairobi. When did the train reach Nairobi? A . Saturday

valentina_108 [34]

Answer:

D.Saturday 8:40am

Step-by-step explanation:

11+8=19 (7)

45+55=100

one hour(100) makes 60 minutes

100-60=40

Therefore the answer is Saturday 8:40am

7 0

3 years ago

Ships A and B are 1,425 feet apart and detect a submarine below them. The angle of depression from ship A to the submarine is 59

andreyandreev [35.5K]

Answer: The distance from ship B to the submarine is 1270.68 feet and the distance from ship A to the submarine is 1084.18 feet.

Step-by-step explanation:

Since we have given that

Distance between Ships A and B = 1425 feet

Angle of depression from ship A to the submarine =59°

Angle of depression from ship B to the submarine = 47°

As shown in the figure below:

Remaining angle will be

$180\textdegree-(47\textdegree+59\textdegree)\\\\=180\textdegree-106\textdegree\\\\=74\textdegree$

So, we will use "Sine formula ":

$\frac{\sin 74\textdegree}{1425}=\frac{\sin 59\textdegree}{B}\\\\B=\frac{1425\times \sin 59\textdegree}{\sin 74\textdegree}\\\\B=1270.68\ feet$

Similarly,

$\frac{\sin 74\textdegree}{1425}=\frac{\sin 47\textdegree}{A}\\\\A=\frac{1425\times \sin 47\textdegree}{\sin 74\textdegree}\\\\A=1084.18\ feet$

Hence, the distance from ship B to the submarine is 1270.68 feet and the distance from ship A to the submarine is 1084.18 feet.

4 0

3 years ago

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Let T: Rn → Rn be an invertible linear transformation, and let S and U be functions from Rn into Rn such that

ipn [44]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

$T: 1 \ R^n \to 1 \ R^n$ is invertible lines transformation

$S[T(x)]=x \ and \ V[T(x)]=x \\\\t'x \ \varepsilon\ 1 R^n\\\\$

T is invertiable linear transformation means that is

$T(x) =A x \\\\ where \\\\ A= n \times n \ \ matrix$

and $\ det(A) \neq 0 \ \ that \ is \ \ A^{-1} \ \ exists$

Let

$V \varepsilon\ a\ R^{n} \ consider \ \ u= A^{-1} v \varepsilon 1 R^n\\\\T(u)= A(A^{-1} v)=(A \ A^{-1}) \\\\ v= I_{n \times n} \cdot v = v$

so,

$s[T(u)]=v[T(u)]\\\\s(v)=v(v) \ \ \forall \ \ v \ \ \varepsilon \ \ 1 R^n$

7 0

2 years ago

Using the photo above:what is the surface area of the rectangular prism

Mandarinka [93]

Answer:

A=592

Step-by-step explanation:

6 0

3 years ago

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What is the value of -3 2/3 +1/3

emmainna [20.7K]

Exact Form:

−10/3

Decimal Form:

−3.3...

Mixed Number Form:

−3 1/3

4 0

2 years ago

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