Answer:v=3.28 m/s
Explanation:
Given
mass of rock ![m=500 gm](https://tex.z-dn.net/?f=m%3D500%20gm)
diameter of circle ![d=2.2 m](https://tex.z-dn.net/?f=d%3D2.2%20m)
radius ![r=\frac{2.2}{2}=1.1 m](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B2.2%7D%7B2%7D%3D1.1%20m)
At highest Point
![mg+N=\frac{mv^2}{r}](https://tex.z-dn.net/?f=mg%2BN%3D%5Cfrac%7Bmv%5E2%7D%7Br%7D)
At highest Point N=0 because mass is just balanced by centripetal Force
thus ![mg=\frac{mv^2}{r}](https://tex.z-dn.net/?f=mg%3D%5Cfrac%7Bmv%5E2%7D%7Br%7D)
![v=\sqrt{gr}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7Bgr%7D)
![v=\sqrt{9.8\times 1.1}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B9.8%5Ctimes%201.1%7D)
![v=\sqrt{10.78}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B10.78%7D)
![v=3.28 m/s](https://tex.z-dn.net/?f=v%3D3.28%20m%2Fs)
Answer:
F₄ = 29.819 N
Explanation:
Given
F₁ = (- 25*Cos 50° i + 25*Sin 50° j + 0 k) N
F₂ = (12*Cos 50° i + 12*Sin 50° j + 0 k) N
F₃ = (0 i + 0 j + 4 k) N
Then we have
F₁ + F₂ + F₃ + F₄ = 0
⇒ F₄ = - (F₁ + F₂ + F₃)
⇒ F₄ = - ((- 25*Cos 50° i + 25*Sin 50° j) N + (12*Cos 50° i + 12*Sin 50° j) N + (4 k) N) = (13*Cos 50° i - 37*Sin 50° j - 4 k) N
The magnitude of the force will be
F₄ = √((13*Cos 50°)² + (- 37*Sin 50°)² + (- 4)²) N = 29.819 N
Almost anything that isn't a metal. Rubber, pure water, wood, and plastic, are all good answers.
Primary Waves
Secondary go only through air, but not water.