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Likurg_2 [28]
4 years ago
12

How are lava and magma the same

Physics
1 answer:
Tom [10]4 years ago
6 0
<span>magma and lava are the same general components, the only difference in the term is that magma has not been erupted. Once magma is erupted it is than redefined as lava. hope that helps</span>
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A rubber ball is dropped and bounces vertically from a horizontal concrete floor. If the ball has a speed of 3 m/s just before s
Ganezh [65]

Answer:

F=12.5N

Explanation:

Net force = rate of change of momentum

F = m*a

so find the change of momentum P

Pdown

P=m*v_1=0.42kg*3m/s

Pup

P=m*v_1=0.42kg*6.5m/s

dP = change in P

dP= 0.42kg (3- -.6.5)m/s =3.99 kg m/s

dT = 0.32 s

so

F = \frac{dP}{dt}=\frac{3.99Kg*m/s}{0.32s} =12.468 N

6 0
3 years ago
A circuit contains two 2,000 resistors connected in parallel. What is the total resistance of the circuit?
GenaCL600 [577]
RT = R1 R2/ R1 + R2

R1 = R2 = 2k ohm

RT = R/2 = 2k/2 = 1k ohm 
5 0
3 years ago
11. एक समान चुम्बकीय क्षेत्र में लम्बवत प्रवेश करने वाले किसी आवेशित कण द्वारा प्राप्त वृत्तीय पथ की
mojhsa [17]

Answer:

<h2> r=mv/Be</h2>

Explanation:

If a positive charge enters a magnetic field at 90 degrees the charge is deflected in a circular path by a force that acts perpendicular to it in line with Flemings right-hand rule

to derive the radius of the path of the charge we apply

F= mv^2/r=Bev

where

m= mass of the electronic charge

e=charge

B=magnetic field

v=average speed

r=radius

 

rearranging we have

r=mv^2/Bev

r=mv/Be

5 0
3 years ago
If the beam carries 1015 electrons per second and is accelerated by a 350 kV source, find the current and power in the beam.
Y_Kistochka [10]

To solve this problem we will apply the concept of current defined as the electron charge flow by the number of electrons per second. That is,

I = q*N

Here q is Flow of electric charge in one second and N the number of electron flow per second.

A the same time the power is described as the applied voltage for the current.

P = VI

We know the charge of electron, q = 1.602 * 10^{-19} Coulombs, then the current is

I = (1.602*10^{-19})(10^{15})

I = 0.1602 mA

And the power in the Beam is

P = VI

P = (350*10^3)(0.1602)

P = 0.05607 Watts

3 0
3 years ago
Which electrical protective device is designed to detect a difference in current between circuit wires and interrupt the circuit
Tamiku [17]
The electrical protective device is designed to detect a difference in current between circuit wires and interrupt the circuit and stop the flow of electricity is : A.GFCI
It stands for Grand Fault circuit interruptor, this will open the circuit when a difference in current is detected between the existing wires
6 0
3 years ago
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