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3 years ago

How are lava and magma the same

1 answer:

6 0

<span>magma and lava are the same general components, the only difference in the term is that magma has not been erupted. Once magma is erupted it is than redefined as lava. hope that helps</span>

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A material the resists the flow of electrons is called a

svp [43]

An insulator which is also called a 'dielectric'.

8 0

3 years ago

Explain the range of effectiveness of each fundamental force by describing the distance that each force influence nearby matter

Bas_tet [7]

Answer:

Actually, gravity is the weakest of the four fundamental forces. Ordered from strongest to weakest, the forces are 1) the strong nuclear force, 2) the electromagnetic force, 3) the weak nuclear force, and 4) gravity.

6 0

3 years ago

Your high-fidelity amplifier has one output for a speaker of resistance 8 Ω. How can you arrange two 8-Ω speakers, one 4-Ω speak

ANTONII [103]

Answer:

(a) 8Ω (b) Ratio = Parra/P8 ohm = 1

Explanation:

Solution

Recall that,

An high-fidelity amplifier has one output for a speaker of resistance of = 8 Ω

Now,

(a) How can two 8-Ω speakers be arranged, when one = 4-Ω speaker, and one =12-Ω speaker

The Upper arm is : 8 ohm, 8 ohm

The Lower arm is : 12 ohm, 4 ohm

The Requirement is = (16 x 16)/(16 + 16) = 8 ohm

(b) compare your arrangement power output of with the power output of a single 8-Ω speaker

The Ratio = Parra/P8 ohm = 1

8 0

3 years ago

What are the smallest parts that make up matter?

Alecsey [184]

The smallest parts that make up different types of matter are called atoms.
Atoms are tiny elements that are made up of literally everything on earth. <span />

3 0

3 years ago

What are the units, if any, of the particle in a box wavefunction. What does this mean?

SIZIF [17.4K]

Answer:

$[\psi]= [Length^{-3/2}]$
This means that the integral of the square modulus over the space is dimensionless.

Explanation:

We know that the square modulus of the wavefunction integrated over a volume gives us the probability of finding the particle in that volume. So the result of the integral

$\int\limits^{x_f}_{x_0} \int\limits^{yf}_{y_0} \int\limits^{z_f}_{z_0} |\psi|^2 \, dz \, dy \, dx$

must be dimensionless, as represents a probability.

As the differentials has units of length

$[dx]=[dy]=[dz]=[Length]$

for the integral to be dimensionless, the units of the square modulus of the wavefunction has to be:

$[\psi]^2 = [Length^{-3}]$

taking the square root this gives us :

$[\psi] = [Length^{-3/2}]$

5 0

3 years ago