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Aleks [24]
3 years ago
7

Only using 1 2 3 4, find a solution that equals 18, 19, 20, and 21

Mathematics
1 answer:
adoni [48]3 years ago
6 0

Answer:

See below, there may be more than one answer

Step-by-step explanation:

4(3+1)+2 = 18

(4+2)(3)+1 = 19

(1)(2+3)(4) = 20

(1+2)(3+4) = 21

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HELPPPPPPPPPPPPPPPPPP AHHHHHHHHHHHHHHHHHHH PLZ
Vadim26 [7]

Answer:

t+8

Step-by-step explanation:

duh

4 0
2 years ago
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Solve the equation. d-5/9=3/9
Aleks04 [339]

Answer:

d = 8/9

Step-by-step explanation:

All you have to do is add 5/9 to both sides.

d - 5/9 + 5/9 = 3/9 + 5/9

d = 89

So, d = 8/9.

8 0
2 years ago
Which line contains the point (1,-3)
Rzqust [24]
There are infinitely many lines that have the point (1,-3).

A line can be expressed as:

y=mx+b, where m=slope and b=y-intercept..

Our only restriction is that it passes through (1,-3) so

-3=1m+b

So as long as the sum of the slope and the y-intercept is equal to -3, that is one of the infinite number of lines that passes through (1, -3)

So we could also say b=-3-m then our infinite lines are:

y=mx-3-m, now any real value of m creates a specific line that passes through the point. ie the first few are

y=x-4, y=2x-5, y=3x-6 or even y=x√2-3-√2


4 0
3 years ago
The drawing shown contains the intersection of two lines.
Phantasy [73]

Answer:

\Huge \boxed{x=5}

\Huge \boxed{121\°}

Step-by-step explanation:

∠1 and ∠2 are vertical angles.

∠1 = ∠2

<u>Part A:</u>

<u></u>

Create an equation and solve for x.

20x + 21 = 30x - 29

Add 29 and -20x on both sides.

20x + 21 + 29 - 20x = 30x - 29 + 29 - 20x

Simplify the equation.

50 = 10x

Divide both sides by 10.

\frac{50}{10} = \frac{10x}{10}

Simplify the equation.

5 = x

Switch sides.

x = 5

<u>Part B:</u>

<u></u>

Let x = 5

20(5) + 21

Distribute.

100 + 21

Add.

= 121

Since both angles are vertical angles, they are equal.

∠1 = 121°

∠2 = 121°

3 0
3 years ago
A'B'C' is the image of AABC under a translation.
lianna [129]

Answer:

no

Step-by-step explanation:

it will be b from baac

3 0
2 years ago
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