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2 years ago

5

Mike's scores on 5 quizzes he took are shown above. In which month was Mike's quiz score equal to the average of his 5 quizzes?

Sept. 72, Oct. 83, Nov. 95, Dec. 77, Jan. 88

1 answer:

Mariana [72]2 years ago

4 0

Answer:

Oct.

Step-by-step explanation:

average = (72 + 83 + 95 + 77 + 88)/5 = 83

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1.) A man invested $600 at 8% per annum for 5 years. Calculate: a.) The simple interest payable b.) The total amount of money th

Bezzdna [24]

Answer:

Following are the solution to this question:

Step-by-step explanation:

Using formula:

$\text{Simple Interest} = \frac{P \times R \times T}{100} \\\\\text{ Total amount} = \text{principle}+ \text{Simple Interest}$

In question (1):

$Principle= \$ 600\\Rate = \ 8 \%\\Time= \ 5$

In point a:

$\to \frac{P \times R \times T}{100} \\\\\to \frac{(600 \times 8 \times 5)}{100}\\\\ \to 240$

In point b:

$\to amount = principle \ +\ simple \ interest$

$= 600 + 240 \\\\= 840$

In question (2):

$Principle= \$ 12,450\\Rate = \ 7.25 \%\\Time= \ 6$

In point a:

$\to \frac{P \times R \times T}{100} \\\\\to \frac{(12,450 \times 7.25 \times 6)}{100}\\\\ \to 5,415.75$

In point b:

$\to amount = principle \ +\ simple \ interest$

$= 12,450 + 5,415.75 \\\\= 17,865.75$

The 3 question is incomplete, that's why it can't be solved.

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Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

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zhenek [66]

Look at the picture.

We have the proportion:

$\dfrac{x}{2}=\dfrac{305}{122}\ \ \ \ |\cdot2\\\\x=\dfrac{305}{61}\\\\x=5\ ft$

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3 years ago

Please help with #19!

ikadub [295]

Answer:

a) yes

b) 2560

Step-by-step explanation:

An exponential function has a common ratio between points uniformly spaced. Here, the data points are 10 years apart.

The ratio of the first two values is 4000/5000 = 0.8.

The ratio of the next two values is 3200/4000 = 0.8.

These ratios are the same, so the data is consistent with an exponential function.

The common ratio can be used to predict the next value. The next value is predicted to be ...

3200 × 0.8 = 2560

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3 years ago