This would result in a biased sample because:
- the survey is surveying elementary kids about a new youth center
most of those kids are more likely than not to want a youth center, so most of them will naturally agree without a doubt for the need of a youth center
- Even the adults at the elementary school are more likely than not to agree with a new youth center because they are teachers and can even benefit from working at the youth center
- in final words the reason why this survey will be biased is because there is no variety in the participants being tested. It is basically just asking teachers she students their preference, excluding the rest of an entire community
please vote my answer brainliest. thanks!
Answer:
=18fx+35gx
Step-by-step explanation:
I think.. Ask your teacher if it's right have a good day :)
Answer:
a)0.6192
b)0.7422
c)0.8904
d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.
Step-by-step explanation:
Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then
z(p)=
where
- Me is the margin of error from the mean
- s is the standard deviation of the population
a.
z(p)=
≈ 0.8764
by looking z-table corresponding p value is 1-0.3808=0.6192
b.
z(p)=
≈ 1.1314
by looking z-table corresponding p value is 1-0.2578=0.7422
c.
z(p)=
≈ 1.6
by looking z-table corresponding p value is 1-0.1096=0.8904
d.
Minimum required sample size for 0.95 probability is
N≥
where
- z is the corresponding z-score in 95% probability (1.96)
- s is the standard deviation (50)
- ME is the margin of error (8)
then N≥
≈150.6
Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.
Answer:
6, 12, 24, 48, 96, 192
Step-by-step explanation:
The first term a1 = 6 and the common ratio is 2.
So it is 6, 6*2, 6*2^2 ....