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Sliva [168]
3 years ago
8

Can i plz have some help with this

Mathematics
2 answers:
inysia [295]3 years ago
6 0

Answer:

320 in

Step-by-step explanation:

Anni [7]3 years ago
5 0
<h3>Answer: 400 </h3>

===================================================

Work Shown:

A = area of parallelogram

A = base*height

A = 20*16

A = 320

B = area of triangle at the very top

B = (1/2)*base*height

B = (1/2)*20*8 ... note: opposite sides of parallelogram are equal

B = 80

C = total area of entire figure

C = A+B

C = 320+80

C = 400

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Read 2 more answers
The vertices of ABC are A(-2, 2), B(6,2), and CO, 8). The perimeter of ABC?
Alexxx [7]

Answer:

Perimeter = 22.809836694575                              

Step-by-step explanation:

A(-2, 2)  ;  B(6,2)  ;  C(0, 8)

AB=\sqrt{\left( 6--2\right)^{2}  +\left(2-2 \right)^{2}  } =\sqrt{64} =8

AC=\sqrt{\left( 0--2\right)^{2}  +\left(8-2 \right)^{2}  } =\sqrt{40} =2\sqrt{10}

BC=\sqrt{\left( 0-6\right)^{2}  +\left(8-2 \right)^{2}  } =\sqrt{72} =6\sqrt{2}

Then

The perimeter of ΔABC = AB + BC + AC

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                                       = 22.809836694575

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2 years ago
Can someone help me write an equation for this problem?
11Alexandr11 [23.1K]
Y=800+175(9)
And then just solve for y.
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3 years ago
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