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Sliva [168]
3 years ago
8

Can i plz have some help with this

Mathematics
2 answers:
inysia [295]3 years ago
6 0

Answer:

320 in

Step-by-step explanation:

Anni [7]3 years ago
5 0
<h3>Answer: 400 </h3>

===================================================

Work Shown:

A = area of parallelogram

A = base*height

A = 20*16

A = 320

B = area of triangle at the very top

B = (1/2)*base*height

B = (1/2)*20*8 ... note: opposite sides of parallelogram are equal

B = 80

C = total area of entire figure

C = A+B

C = 320+80

C = 400

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What are the foci of the hyperbola with equation 5y^2-4x^2=20?
shusha [124]
The foci of the hyperbola with equation 5y^2-4x^2=20 will be given as follows:
divide each term by 20
(5y^2)/20-(4x^2)/20=20/20
simplifying gives us:
y^2/4-x^2/5=1
This follows the standard form of the hyperbola
(y-k)²/a²-(x-h)²/b²=1
thus
a=2, b=√5 , k=0, h=0
Next we find c, the distance from the center to a focus.
√(a²+b²)
=√(2²+(√5)²)
=√(4+5)
=√9
=3
the focus of the hyperbola is found using formula:
(h.h+k)
substituting our values we get:
(0,3)
The second focus of the hyperbola can be found by subtracting c from k
(h,k-c)
substituting our values we obtain:
(0,-3)

Thus we have two foci
(0,3) and (0,-3)
5 0
3 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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Answer:

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