Answer:

Step-by-step explanation:
Hi!
Lets call:
T = temprature of the object
T₀ = temperature of surroundings
t = time
The rate of change of T is its derivative with respecto to time. If T > T₀, the object looses heat, so T decreases. Then, being k > 0:

In this case T₀ = 70ºF and k = 0.05/min. Then the differential equation is:

Distribute -2(x - 3)
4x - 2x + 6 = 10 + -9
Simplify
2x = -5
x = -2.5
Answer:
tanA=34⟹sinA=332+42−−−−−−√=35
Now, we have
sinAcosA=tanA
⟹3/5cosA=tanA
⟹cosA=13×54×3
⟹cosA=45
⟹cosAsinA=4×35×5=1225
Step-by-step explanation: