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Gre4nikov [31]
2 years ago
9

The equation y=19x relates proportional quantities x and y. what is the value of x when y is 4?

Mathematics
2 answers:
Romashka [77]2 years ago
4 0

Answer:  The required value of x is \dfrac{4}{19}.

Step-by-step explanation:  Given that the following equation relates proportional quantities x and y :

y=19x~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

We are to find the value of x when y is 4.

To find the value of x, we must substitute y = 4 in equation (i) and find the corresponding value of x.

From equation (i), we get

y=19x\\\\\Rightarrow 4=19x\\\\\Rightarrow x=\dfrac{4}{19}.

Thus, the required value of x is \dfrac{4}{19}.

azamat2 years ago
3 0
X = 36

simplify both sides of the equation, isolate the variable,

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y=\frac{7-3x}{j}

Step-by-step explanation:

First, subtract 3x. This leaves you with jy=7-3x. Then, divide by j, leaving you with y=\frac{7-3x}{j} .

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Form a quadratic equation with roots (1+√3) and (1-√3)​
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2 years ago
Solve the system of equations. 2x y = 7 5x y = 9
lana [24]
Are you missing something?
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7 0
3 years ago
After being treated with chemotherapy, the radius of the tumor decreased by 23%. What is the corresponding percentage decrease i
Crazy boy [7]

Answer:

The volume of the tumor experimented a decrease of 54.34 percent.

Step-by-step explanation:

Let suppose that tumor has an spherical geometry, whose volume (V) is calculated by:

V = \frac{4\pi}{3}\cdot R^{3}

Where R is the radius of the tumor.

The percentage decrease in the volume of the tumor (\%V) is expressed by:

\%V = \frac{\Delta V}{V_{o}} \times 100\,\%

Where:

\Delta V - Absolute decrease in the volume of the tumor.

V_{o} - Initial volume of the tumor.

The absolute decrease in the volume of the tumor is:

\Delta V = V_{o}-V_{f}

\Delta V = \frac{4\pi}{3}\cdot (R_{f}^{3}-R_{o}^{3})

The percentage decrease is finally simplified:

\%V = \left[1-\left(\frac{R_{f}}{R_{o}}\right)^{3} \right]\times 100\,\%

Given that R_{o} = R and R_{f} = 0.77\cdot R, the percentage decrease in the volume of tumor is:

\%V = \left[1-\left(\frac{0.77\cdot R}{R}\right)^{3} \right]\times 100\,\%

\%V = 54.34\,\%

The volume of the tumor experimented a decrease of 54.34 percent.

5 0
3 years ago
I need help, can someone please help me
zaharov [31]

Answer:

slope (3,1) using rise over run y-intercept -1

Step-by-step explanation:

Starting at your y-intercept -1 and going up three and 1 to the right you get to your next point on the graph

5 0
3 years ago
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