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Gre4nikov [31]
2 years ago
9

The equation y=19x relates proportional quantities x and y. what is the value of x when y is 4?

Mathematics
2 answers:
Romashka [77]2 years ago
4 0

Answer:  The required value of x is \dfrac{4}{19}.

Step-by-step explanation:  Given that the following equation relates proportional quantities x and y :

y=19x~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

We are to find the value of x when y is 4.

To find the value of x, we must substitute y = 4 in equation (i) and find the corresponding value of x.

From equation (i), we get

y=19x\\\\\Rightarrow 4=19x\\\\\Rightarrow x=\dfrac{4}{19}.

Thus, the required value of x is \dfrac{4}{19}.

azamat2 years ago
3 0
X = 36

simplify both sides of the equation, isolate the variable,

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Which number line shows the estimate of 22 in the correct interval of integers?​
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3 years ago
the numbers 1,2,3,4, and 5 are written on slips of paper, and 2 slips are drawn at random one at a time without replacet. find t
Tresset [83]

Consider such events:

A - slip with number 3 is chosen;

B - the sum of numbers is 4.

You have to count Pr(A|B).

Use formula for conditional probability:

Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr(B)}.

1. The event A\cap B consists in selecting two slips, first is 3 and second should be 1, because the sum is 4. The number of favorable outcomes is exactly 1 and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event A\cap B is

Pr(A\cap B)=\dfrac{1}{20}.

2. The event B consists in selecting two slips with the sum 4. The number of favorable outcomes is exactly 2 (1st slip 3 and 2nd slip 1 or 1st slip 1 and 2nd slip 3) and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event B is

Pr(B)=\dfrac{2}{20}=\dfrac{1}{10}.

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Pr(A|B)=\dfrac{\frac{1}{20} }{\frac{1}{10} }=\dfrac{1}{2}.

Answer: \dfrac{1}{2}.

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