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s2008m [1.1K]
3 years ago
10

True or False? It's not possible to build a triangle with side lengths of 3, 3, and 3.

Mathematics
2 answers:
Rzqust [24]3 years ago
7 0
False, you can make a triangle with 3 sides that are 3. It would be a equilateral triangle <span />
Aliun [14]3 years ago
4 0
FALSE!\\\\thats\ triangle\ is\ equilateral\ triangle.

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Find an equation for a line<br> perpendicular to y= 3x – 5 , with a y-<br> intercept of -2
damaskus [11]

Answer:

Since the lines are Perpendicular..

The Product of their Gradients = -1

m'm"=-1

m' from y=3x - 5 is 3

3.m" = -1

m" = -1/3.

Since Intercept on y axis = -2...

That of x at that point is =0

y-y' = m"(x-x")

y-(-2) = -1/3( x - 0)

y+2 = -1/3(x)

Multiplying through by 3

3y + 6 = -x

3y + x = -6. This is your Equation

To verify this.

Let's turn it into the Intercept form which is

x/a + y/b = 1

To get 1 at the right hand side... Divide through by -6

3y/-6 + x/-6 = 1

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You could see directly below y is its intercept and thats -2

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3 years ago
How many ways can 13 students line up for lunch
Delicious77 [7]

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Step-by-step explanation:

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7 0
3 years ago
Can someone answer this please
Ulleksa [173]
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2 years ago
Find the GCF of numbers 132 and 242 using prime factorization.
tatyana61 [14]

Answer:

1)Find the prime factorization of 242

242 = 2 × 11 × 11Step-by-step explanation:

2)Find the prime factorization of 132

132 = 2 × 2 × 3 × 11

3)To find the GCF, multiply all the prime factors common to both numbers:

Therefore, GCF = 2 × 11

The lost one 4) GCF = 22

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Black_prince [1.1K]

Answer:

triangle

Step-by-step explanation:

6 0
3 years ago
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