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tino4ka555 [31]
4 years ago
8

Use the subtraction property of equality to complete the following statement:

Mathematics
1 answer:
Delicious77 [7]4 years ago
3 0
<span> 10x + 6 = 21
first subtract 6 from both sides of the equation
10x=15
so I believe the answer you are looking for is 10x=15

If you take this one step further and solve for x then you divide both sides of the equation by 10 so then the solution is x=1.5



</span>
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Help me with this very pls. I will give you the brainliest and a thanks!! :)) Can you do 1 and 4 thanks!! :)))
lubasha [3.4K]
Answer: 1. 12 and 4 I think
4 0
3 years ago
Will give brainliest.
In-s [12.5K]

Answer:

y = 3x -8

Step-by-step explanation:

I find it convenient to start with a version of the point-slope form of the equation for a line. That is, for point (h, k) and slope m, ...

y = m(x -h) +k

For your m=3 and (h, k) = (3, 1), this equation becomes ...

y = 3(x -3) +1

Eliminating parentheses puts this in the form you desire:

y = 3x -8

6 0
3 years ago
How many hours would it take to get from Miami FL to New Hampshire?
bonufazy [111]
It would most likely take 3-4 hours, maybe even 5.
8 0
3 years ago
The product of two irrational numbers is. Rational
Snowcat [4.5K]

Answer:

So the statement:

"The product of two irrational numbers is rational." is false.

Step-by-step explanation:

The product of two irrationals can be irrational or rational.

Example:

\sqrt{2} \cdot \sqrt{2}=2

\sqrt{2} is irrational but when you multiply it to itself the output is rational.

Example:

\sqrt{2} \cdot \sqrt{3}=\sqrt{6}

\sqrt{2} \text{ and } \sqrt{3} are irrational and when you multiply them you get an irrational answer of \sqrt{6}.

So the statement:

"The product of two irrational numbers is rational." is false.

5 0
3 years ago
A deck of cards contains RED cards numbered 1,2,3,4,5, BLUE cards numbered 1,2,3, and GREEN cards numbered 1,2,3,4,5,6. If a sin
Tatiana [17]

Answer: 1/52

Step-by-step explanation:

A deck of cards contains 52 cards

Red cards are numbered 1,2,3

Blue cards are numbered 1,2,3,4,5,6

Green cards are numbered 1,2

Number of Red card = 3

Number of blue card = 6

Number of Green card = 2

Let Pr(R) = Probability of picking a Red card

Let Pr(B) = probability of picking a blue card

Let Pr(G) = probability of picking a green card

Let Pr(RE) = Probability of picking a red even card

Let Pr(RO) = probability of picking a red odd card

Let Pr(BE) =probability of picking a blue even card

Let Pr(BO) = probability of picking a blue odd card

Let Pr(GE) = probability of picking a green even card

Let Pr(GO) = probability of picking a green odd card

Pr(R) = 3/52

Since we have 3 red cards,

Pr(RE) = 1/3

Pr(RO) =2/3

Pr(B) = 6/52

= 3/26

Since we have 6 blue cards ,

Pr(BE) = 3/6

= 1/2

Pr(BO) = 3/6

= 1/2

Pr (G) = 2/52

= 1/26

Since we have 2 green cards,

Pr(GE) = 1/2

Pr(GO) = 1/2

The probability of picking a Green card and an odd green card is

Pr(G) n pr(GO)

1/26 * 1/2

= 1/52

5 0
3 years ago
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