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tino4ka555 [31]
4 years ago
8

Use the subtraction property of equality to complete the following statement:

Mathematics
1 answer:
Delicious77 [7]4 years ago
3 0
<span> 10x + 6 = 21
first subtract 6 from both sides of the equation
10x=15
so I believe the answer you are looking for is 10x=15

If you take this one step further and solve for x then you divide both sides of the equation by 10 so then the solution is x=1.5



</span>
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A nunber greater than 0 is called
kirza4 [7]
Hey there! 

Negatives numbers are less than 0 and positive numbers are  greater  than 0

Just think of it on a number line, the numbers  on the left of 0 is negative numbers and the numbers to the right of 0 is positive numbers

Answer: Positive numbers

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Pls help me!
Snowcat [4.5K]
You have to multiply 85x2.65 and it equals 225.25. This is the answer.
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Line segment XY begins at (-6,4) and ends at (-2,4). The segment is reflected over the x-axis and translated left 3 units to for
Marat540 [252]

Line segment XY begins at (-6,4) and ends at (-2,4); XY is reflected over the x-axis and translated left 3 units to form line segment X'Y' which has a length of 4 units.

<h3>What is a system of equations?</h3>

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

Line segment XY begins at (-6,4) and ends at (-2,4). Hence:

XY = \sqrt{(4-4)^2 + (-2 +6)^2} \\\\XY = \sqrt{0+16} \\\\XY = \sqrt{16} \\\\XY = 4

XY is reflected over the x-axis and translated left 3 units to form line segment X'Y'. Hence:

XY = X'Y' = 4 units

Line segment XY begins at (-6,4) and ends at (-2,4); XY is reflected over the x-axis and translated left 3 units to form line segment X'Y' which has a length of 4 units.

Find out more on equation at:

brainly.com/question/2972832

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5 0
2 years ago
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damaskus [11]
They are congruent is the answer
6 0
3 years ago
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The diagram shows 5cm×5cm×5cm cube calculate the length of the diagonal ab
mario62 [17]

Answer:

AB = 5\sqrt{3} cm

Step-by-step explanation:

As we can see from the figure, BCDE is a square with each corner equal to 90°.

So that, BDE is a right triangle with corner BED equal to 90°

As BDE is a right triangle, according to Pythagoras theorem, we have:

         BD^{2} = BE^{2} +ED^{2} = 5^{2} + 5^{2} = 25 + 25 = 50cm

As the diagram s the cube, so that it can be seen that AD is perpendicular to the surface BCDE

=> AD is perpendicular to BD

=> ADB is the right triangle with corner ADB equal to 90°.

As ADB is the right triangle, ccording to Pythagoras theorem, we have:

AB^{2} =AD^{2} + BD^{2} = 5^{2} +50 = 25 +50 = 75 cm

=> AB = \sqrt{75}  = 5\sqrt{3} cm

Conclusion: AB = 5\sqrt{3}cm

4 0
3 years ago
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