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yawa3891 [41]
3 years ago
6

5(1+4m)=2(3+10m) Please help. Show work please

Mathematics
2 answers:
stealth61 [152]3 years ago
8 0
Distribute first...
5(1)=5
5(4m)=20m
So for the left side it's 5+20m
Now u have to do the same thing for the right side
2(3)=6
2(10m)=20m
So for the right side it's 6+20m
Now that u have solved both sides u have to isolate the m
5+20m=6+20m
-5 -5
----------------------
20m=1+20m
-20m -20m
------------------------
0=1
Therefore there is no solution
jarptica [38.1K]3 years ago
5 0
5 times 1 which is 6+4m
6+10m
Combine light terms
12+14m
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It differs because dilation changes the shape but not the orientation or place the shape is located.

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pogonyaev
Y=4x-21 I’m pretty sure is the answrr.

7 0
2 years ago
How many different perfect cubes are among the positive actors of 2021^2021
9966 [12]

Answer:

hope this helps :D

Step-by-step explanation:

Perfect cube factors:

If a number is a perfect cube, then the power of the prime factors should be divisible by 3.

Example 1:Find the number of factors of293655118 that are perfect cube?

Solution: If a number is a perfect cube, then the power of the prime factors should be divisible by 3. Hence perfect cube factors must have

2(0 or 3 or 6or 9)—– 4 factors

3(0 or 3 or 6)  —–  3  factors

5(0 or 3)——- 2 factors

11(0 or 3 or 6 )— 3 factors

Hence, the total number of factors which are perfect cube 4x3x2x3=72

Perfect square and perfect cube

If a number is both perfect square and perfect cube then the powers of prime factors must be divisible by 6.

Example 2: How many factors of 293655118 are both perfect square and perfect cube?

Solution: If a number is both perfect square and perfect cube then the powers of prime factors must be divisible by 6.Hence both perfect square and perfect cube must have

2(0 or 6)—– 2 factors

3(0 or 6) —– 2 factors

5(0)——- 1 factor

11(0 or 6)— 2 factors

Hence total number of such factors are 2x2x1x2=8

Example 3: How many factors of293655118are either perfect squares or perfect cubes but not both?

Solution:

Let A denotes set of numbers, which are perfect squares.

If a number is a perfect square, then the power of the prime factors should be divisible by 2. Hence perfect square factors must have

2(0 or 2 or 4 or 6 or 8)—– 5 factors

3(0 or 2 or 4 or 6)  —– 4 factors

5(0 or 2or 4 )——- 3 factors

11(0 or 2or 4 or6 or 8 )— 5 factors

Hence, the total number of factors which are perfect square i.e. n(A)=5x4x3x5=300

Let B denotes set of numbers, which are perfect cubes

If a number is a perfect cube, then the power of the prime factors should be divisible by 3. Hence perfect cube factors must have

2(0 or 3 or 6or 9)—– 4 factors

3(0 or 3 or 6)  —–  3  factors

5(0 or 3)——- 2 factors

11(0 or 3 or 6 )— 3 factors

Hence, the total number of factors which are perfect cube i.e. n(B)=4x3x2x3=72

If a number is both perfect square and perfect cube then the powers of prime factors must be divisible by 6.Hence both perfect square and perfect cube must have

2(0 or 6)—– 2 factors

3(0 or 6) —– 2 factors

5(0)——- 1 factor

11(0 or 6)— 2 factors

Hence total number of such factors are i.e.n(A∩B)=2x2x1x2=8

We are asked to calculate which are either perfect square or perfect cubes i.e.

n(A U B )= n(A) + n(B) – n(A∩B)

=300+72 – 8

=364

Hence required number of factors is 364.

8 0
3 years ago
I need help 0.259 written out as a fraction or mixed number?
oksano4ka [1.4K]

1) To write 0.259 as a fraction let's firstly rewrite as

\frac{259}{1000}

2) Count the digits the dot has gone to the left. Each digit to the left means divided by ten. Like this:

3) Since it starts with a zero then it can't be a Mixed number. So it is an improper fraction. No further simplification could be done.

4 0
1 year ago
9x + 8 y = -6<br> -9x - 9y - 9<br> Elimination
kolezko [41]

Answer:

x = 2, y = -3

Step-by-step explanation:

Add them together and get

9x + 8y - 9x - 9y = -6 + 9

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so y = -3.

Sub it into the first equation and get

9x + 8(-3) = -6

9x - 24 = -6

9x = -6 + 24 = 18

x = 18/9 = 2

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2 years ago
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