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trapecia [35]
3 years ago
8

Susan is attending a talk at her son's school. There are 8 rows of 10chairs where 54 parents are sitting. Susan notices that eve

ry parent is either sitting on their own or next to just one other person. What is the largest possible number of adjacent empty chairs in a single row at that talk?
Mathematics
1 answer:
kozerog [31]3 years ago
4 0

Answer:

The largest possible number of adjacent empty chairs in a single row is 3

Step-by-step explanation:

The parameters given are;

The number of chairs = 8 × 10 = 80 chairs

The number of parents = 54

Sitting arrangements of parents = Alone or to one other person

Therefore;

The maximum number of parents on a row = 1 + 1 + 0 + 1 + 1 + 0 + 1 + 1 + 0 + 1 = 7

Hence when the rows have the maximum number of parents occupying the seats we have for the 8 rows;

7 + 7 + 7 + 7 + 7 + 7 + 7 + 7 = 56

But there are only 54 parents, therefore, up to the 7th row will have 7 parents while the 8th row will have only 5 parents to make the possible sitting arrangement to be as follows;

7 + 7 + 7 + 7 + 7 + 7 + 7 + 5 = 54

The sitting arrangement for the 8th row is therefore

1 + 1 + 0 + 1 + 1 + 0 + 1 + 0 + 0 + 0

Hence there will be three empty seats in the 8th row making the largest possible number of adjacent empty chairs in a single row = 3.

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Answer:

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Step-by-step explanation:

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2 years ago
Hey ok i need help on this question ive been stuck on it for a couple minutes haha
Len [333]

Answer:

The side s has a length of 4 and side q has a length of 4\sqrt{3} ⇒ F

Step-by-step explanation:

In the 30°-60°-90° triangle, there is a ratio between its sides

side opp (30°) : side opp (60°) : hypotenuse

       1               :         \sqrt{3}            :        2

In the given triangle

∵ The side opposite to 30° is s

∵ The side opposite to 60° is q

∵ The hypotenuse is 8

→ Use the ratio above to find the lengths of s and q

side opp (30°) : side opp (60°) : hypotenuse

       1               :         \sqrt{3}            :        2

       s               :          q             :        8

→ By using cross multiplication

∵ s × 2 = 1 × 8

∴ 2s = 8

→ Divide both sides by 2

∴ s = 4

∴ The length of s is 4

∵ q × 2 = \sqrt{3} × 8

∴ 2q = 8\sqrt{3}

→ Divide both sides by 2

∴ q = 4\sqrt{3}

∴ The length of q is 4\sqrt{3}

7 0
3 years ago
I am very behind in edge, is anyone willing to help me?
Vilka [71]

Answer:

Whats the question?

3 0
2 years ago
Read 2 more answers
What is the domain and range of the relation shown in
Leya [2.2K]

Answer:

Domain : {10, 15, 19, 32}

Range: {-1, 5, 9}

Step-by-step explanation:

As the table of the relation is given as follows:

<em>X                Y</em>

<em>10               5</em>

<em>15               9</em>

<em>19               -1</em>

<em>32             5  </em>

From this table, we can define the relation by combining the ordered pairs from the table. Each and every order pair consists of x-coordinate and corresponding y-coordinate of any corresponding point.

So, the relation from the table can be made as follows:

                            relation : {(10, 5), (15, 9), (19, -1), (32, 5)}

Domain of a relation consists of all the x-coordinates (first elements) of order pairs.

Range of a relation consists of all the y-coordinates (second elements) of ordered pairs.

So, domain  and range of relation will be as follows:

                                  Domain : {10, 15, 19, 32}

                                  Range: {-1, 5, 9}

<em>Note: If there is any </em><em>duplicate</em><em> element in any x or y-coordinate of any ordered pair, it will be written only </em><em>once </em><em>when we determine domain and range. Here, in this example, 5 is duplicate, so, it will be mentioned only one time when we determine the range of this relation.</em>

Keywords:  domain, relation, range

Learn more about domain and range of a relation from brainly.com/question/11422136

#learnwithBrainly

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Answer:

C

Step-by-step explanation:

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3 years ago
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