20+x>70
-20. -20. on both sides to even it out
x>50 is the answer
Answer:
ln(125) ≈ 4.828314
Step-by-step explanation:
The relevant log relation is ...
log(a^b) = b·log(a)
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This means your expression is equivalent to ...
3·ln(5) = ln(5^3) = ln(125) ≈ 4.828314
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The "exact" answer is ln(125).
Answer: a) , where 'A' is the value of car after 't' years.
b) $12446.784
Step-by-step explanation:
Given: A new car that sells for $21,000 depreciates (decreases in value) 16% each year.
Then a function that models the value of the car will be
, where 'P' is the selling price of car, 'r' is the rate of depreciation in decimal, 't' is the time in years and 'A' is the value of car after 't' years.
Thus after substituting given value, the function becomes
To find the value after 3 years, substitute t=3 in the above function.
Hence the value of car after 3 years=$12446.784
Answer:
3x-2c=5
3x=5-2c
x=<u>5</u><u>-</u><u>2</u><u>c</u>
3
Answer:
there is no solution
Step-by-step explanation:
y + 7 = 3x
6x - 2y = 6 which can be simplied to be 3x - y = 6 (divide by 2)
let y = 3x - 7
substitute: 3x -(3x - 7) = 6
3x - 3x + 7 = 6
7 ≠ 6 therefore, no solution
