The answer is the first one
This is your answer, i hope this help if you have any questions let me know
Answer:
12.8 IN.
Step-by-step explanation:
So, what exactly is perimeter?
Perimeter= 2L+ 2W
In this question we were given the length.ie.Base and the perimeter itself.
●Length is 39 In.
●Perimeter is 103.6 In.
●We don't know the width.
But, as per given the question, we know that;
1 length = 39 In.
2 lengths= 78 In.
Now that we know the <u>total</u><u> </u><u>length</u><u> </u><u>we</u><u> </u><u>can</u><u> </u><u>find</u><u> </u><u>the</u><u> </u><u>total</u><u> </u><u>width</u><u>.</u>
See as follows,
103.6 - 78= 25.6
<u>2</u><u> </u><u>widths</u><u>=</u><u> </u><u>25</u><u>.</u><u>6</u>
<u>1</u><u> </u><u>width</u><u>=</u><u> </u><u>25</u><u>.</u><u>6</u><u>÷</u><u>2</u>
<u>=</u><u>12</u><u>.</u><u>8</u><u> </u><u>In</u>
Answer:
D, F.
Step-by-step explanation:
D and F contain x^2.
The product of the given two matrices comes out to be ![\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D)
Here we are given the 2 matrices as follows-
![\left[\begin{array}{ccc}7&-2\\-6&2\end{array}\right] \left[\begin{array}{ccc}1&1\\3&3.5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%26-2%5C%5C-6%262%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%261%5C%5C3%263.5%5Cend%7Barray%7D%5Cright%5D)
To find the product of 2 matrices, the number of columns in the first matrix must be equal to the number of rows in the second matrix.
Here since both of the matrices are 2 × 2, their product is possible.
Now, to find the product, we need to multiply each element in the first row by each element of the 1st column of the second matrix and then find their sum. Similarly, we do this for all rows and columns.
Therefore,
![\left[\begin{array}{ccc}(7*1)+(-2*3)&(7*1)+(-2*3.5)\\(-6*1)+(2*3)&(-6*1)+(2*3.5)\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%287%2A1%29%2B%28-2%2A3%29%26%287%2A1%29%2B%28-2%2A3.5%29%5C%5C%28-6%2A1%29%2B%282%2A3%29%26%28-6%2A1%29%2B%282%2A3.5%29%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}(7)+(-6)&(7)+(-7)\\(-6)+(6)&(-6)+(7)\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%287%29%2B%28-6%29%26%287%29%2B%28-7%29%5C%5C%28-6%29%2B%286%29%26%28-6%29%2B%287%29%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D)
Thus, the product of the given two matrices comes out to be ![\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D)
Learn more about matrices here-
brainly.com/question/13595915
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