Answer:
373.8mmHg
Step-by-step explanation:
a =height (in km) above sea level,
the pressure P(a) (in mmHg) is approximated given as
P(a) = 760e–0.13a .
To determine the atmospheric pressure at 5.458 km, then we will input into the equation
P(5.458km) = 760e–0.13a .
= 760e^(-0.13×5.458)
=760e^-(0.70954)
= 760×0.4919
=373.8mmHg
Therefore, the atmospheric pressure at 5.458 km is 373.8mmHg
Answer:
D
Step-by-step explanation:
Using the Sine rule in Δ QRS , that is
=
, that is
=
( cross- multiply )
12× sinQ = 15 × sin50.1° ( divide both sides by 12 )
sinQ =
, thus
Q =
(
) ≈ 73.5° ( to the nearest tenth )
Answer:
$28
Step-by-step explanation:
40% of 20 is 8
20 + 8 = 28
Answer:

Step-by-step explanation:
Given


Required
Determine the image P'
P' is calculated by multiplying P and k.
i.e.

This gives:



<em>Hence, the image P' after dilating P is (-10,-8)</em>