Answer:
![(x-5)^2+(y+7)^2=49](https://tex.z-dn.net/?f=%28x-5%29%5E2%2B%28y%2B7%29%5E2%3D49)
Step-by-step explanation:
Use
for the equation of a circle in standard form with radius
and center
. Therefore, the equation of the circle in standard form is ![(x-5)^2+(y+7)^2=49](https://tex.z-dn.net/?f=%28x-5%29%5E2%2B%28y%2B7%29%5E2%3D49)
Answer:the answer is y= 10x + 35
Step-by-step explanation:
3 significant figures
0 is only significant if it is enclosed by significant figure.
here 0 is enclosed by significant figures 1 and 5 and is therefore significant.
105 has 3 significant figures
Answer:
Yes
Step-by-step explanation:
When you divide it, it has no remainder.
Hope this helps
Answer:
474.84 ft of fencing is needed
Step-by-step explanation:
We know that the angles of a triangle sum up 180º. We already know 2 of the triangle's angles (55º and 63º). Therefore the third angle measures:
180 - 55 - 63 = 62.
To know how much fencing is needed, we need the perimeter of the triangle, so we need to find out how much the other sides of the lot measure.
We will use law of sins to solve this problem.
First we solve for y:
![\frac{150}{sin55}= \frac{y}{sin63} \\y=150 (sin63)/(sin55)\\y=133.65/.8191\\y=163.16](https://tex.z-dn.net/?f=%5Cfrac%7B150%7D%7Bsin55%7D%3D%20%5Cfrac%7By%7D%7Bsin63%7D%20%20%5C%5Cy%3D150%20%28sin63%29%2F%28sin55%29%5C%5Cy%3D133.65%2F.8191%5C%5Cy%3D163.16)
Now we solve for the other side of the lot, x:
![\frac{150}{sin55}=\frac{x}{sin62}\\ x=150(sin62)/(sin55)\\x=150(.8829)/.8191\\x=132.435/.8191\\x=161.68](https://tex.z-dn.net/?f=%5Cfrac%7B150%7D%7Bsin55%7D%3D%5Cfrac%7Bx%7D%7Bsin62%7D%5C%5C%20%20x%3D150%28sin62%29%2F%28sin55%29%5C%5Cx%3D150%28.8829%29%2F.8191%5C%5Cx%3D132.435%2F.8191%5C%5Cx%3D161.68)
Now that we have the measures of all the sides we sum them up
total fencing needed= 150 + 163.16 + 161.68 = 474.84