<span>%Antifreeze=<span><span>V<span>Antifreeze</span></span><span>V<span>Fluid</span></span></span></span>
<span><span>V<span>Fluid</span></span>=<span><span>V<span>Antifreeze</span></span><span>%Antifreeze</span></span></span>
<span><span>V<span>Antifreeze</span></span>=<span>V<span>fluid</span></span>∗%Antifreeze</span>
I want to find the amount of antifreeze in a 15 quart solution with 30% antifreeze
<span><span>V<span>Antifreeze</span></span>=15∗0.30</span> =18/4 quarts of antifreeze
Similarly, I want to find the amount of antifreeze in a 15 quart solution with 35% antifreeze first.
<span><span>V<span>Antifreeze</span></span>=15∗0.35</span> = 21/4 quarts of antifreeze
<span>the difference between 21/4 and 18/4 is 3/4 quarts, which is the amount of pure antifreeze I've added in.
</span><span>
SO the V_fluid I replaced with 3/4 quarts of antifreeze is (3/4)/ 0.35</span>
Im not in expert at this but i did the best i could im 80% sure this is the anser if not im sorry x > 30
Answer:
y= -1/2x + 1/2
Step-by-step explanation:
First, use the point-slope formula: y-y1 = m(x-x1)
y-2 = -1/2(x-(-3))
y-2= -1/2x + -1.5
(subtract 2 from both sides)
y = -1/2x + 1/2
The correct answer is choice C. Here is the reason. If you substitute the information into the formula this is what it would be:
A = bh/2
13 = x (6x + 1)/2
13 = (6x^2 + x)/2
26 = 6x^2 + x
0 = 6x^2 + x - 26
