All categories

3 years ago

sean earns 4.50 per hour more than the trainee during one 8 hour day they earn a total of $284 how much does Sean make per hour

1 answer:

3 0

1) Let Sean=x and Tyrone=y. But we want to get what Sean earns and what Tyrone earns in terms of one variable so we say that Tyrone=x-4.5 (beacuse he makes $4.50 per hour less than Sean). 2) Now set up the equation: 8 hours time x plus 8 hours times x-4.5 equals 284 OR
8x+8(x-4.5)=284 3) Solve for x 8x+8(x-4.5)=284 8x+8x-36=284 16x=320 x=20 So Sean makes $20 per hour and Tyrone makes $15.50 per hour

You might be interested in

You need $3,000 to buy a new stereo for your car. If you have $1,200 to invest at

DiKsa [7]

Answer:

15 years and 8 months

Step-by-step explanation:

I used the formula for compound interest as shown below and solved for the unknown, time.

Since our interest is compounded annually (So once a year) our m value is 1.

3 0

2 years ago

If P(x)= -x^3-2x^2+2x-2 and A(x)= x+2. Use the remainder when P(x) is divided by A(x).

777dan777 [17]

Zbdhhsbzzbbdeh yettttt

7 0

3 years ago

A standard weight known to weigh 10 grams. Some suspect bias in weights due to manufacturing process. To assess the accuracy of

notsponge [240]

Answer:

a) The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams

b) 49 measurements are needed.

Step-by-step explanation:

Question a:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.98}{2} = 0.01$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.01 = 0.99$ , so Z = 2.327.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 2.327\frac{0.0003}{\sqrt{5}} = 0.00031$

The lower end of the interval is the sample mean subtracted by M. So it is 10.0044 - 0.00031 = 10.00409 grams

The upper end of the interval is the sample mean added to M. So it is 10 + 0.00031 = 10.00471 grams

The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams.

(b) How many measurements must be averaged to get a margin of error of +/- 0.0001 with 98% confidence?

We have to find n for which M = 0.0001. So

$M = z\frac{\sigma}{\sqrt{n}}$

$0.0001 = 2.327\frac{0.0003}{\sqrt{n}}$

$0.0001\sqrt{n} = 2.327*0.0003$

$\sqrt{n} = \frac{2.327*0.0003}{0.0001}$

$(\sqrt{n})^2 = (\frac{2.327*0.0003}{0.0001})^2$

$n = 48.73$

Rounding up

49 measurements are needed.

7 0

2 years ago

90 POINTS!!! PLEASEE HELP AND SHOW WORK. I WILL GIVE BRAINLIEST IF ALL WORK IS SHOWN THANKSS.

konstantin123 [22]

Answer:

18. 3.3years

Step-by-step explanation:

18. 20,000 - (20,000 - .15x) = 10,000

15% of 20,000 is 3,000

5 0

3 years ago

You have two lines. Line A measures 12/16, and line B measures 3/4.

hram777 [196]

Answer:

Step-by-step explanation:

Let's compare the two values of 12/16 and 3/4.

Notice that 12/16 isn't a simplified fraction; both the numerator and denominator are divisible by 4. So divide the top and bottom by 4:

12 / 4 = 3

16 / 4 = 4

We are left with:

12/16 = 3/4

Now, we see that Line A and Line B are equal in length, so the answer is B.

<em>~ an aesthetics lover</em>

8 0

3 years ago

Read 2 more answers