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3 years ago

Can someone help me with this?? explain if you would like

Mathematics

1 answer:

vova2212 [387]3 years ago

5 0

Answer:

answer is 38 yd

Step-by-step explanation:

area of square =1444 yd^2

z^2=1444 yd^2

z= $\sqrt{1444$ yd^2

z=38 yd

Hope this helps u!!

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A triangle has two sides of length 4 and 13. What is the smallest possible whole-number length for the third side?

AfilCa [17]

Answer:

9 i think but make sure

Step-by-step explanation:

well, a squared+b squared=c squared

13 squared-4 squared is 9 squared

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3 years ago

Find the general solution of the given differential equation.

Elina [12.6K]

Answer:

$y=-x\,cos\,x+Cx$

There are no transient terms.

Step-by-step explanation:

Given: $x\,\frac{dy}{dx} -y=x^2\,sin\,x$

To find: general solution of the differential equation and the transient terms in the general solution.

Solution:

For an equation of the form $\frac{dy}{dx}+yp(x)=q(x)$ ,

solution is given by $ye^{\int {p(x)} \, dx }$ = ∫ q(x) $e^{\int {p(x)} \, dx }$ dx

The given equation $x\,\frac{dy}{dx} -y=x^2\,sin\,x$ can be written as $\frac{dy}{dx}-\frac{y}{x}=x\,sin\,x$

Here,

$p(x)=\frac{-1}{x}\,,\,q(x)=x\,sin\,x$

$e^{\int{p(x)} \, dx } =e^{\int{\frac{-1}{x} } \, dx } =e^{-ln(x)} =e^{ln(x^{-1} )}=x^{-1}=\frac{1}{x}$

So,

the solution is $\frac{y}{x}=\int \frac{1}{x}x\,sin\,x\,dx$

$\frac{y}{x} =\int\,sin\,x\,dx\\\\\frac{y}{x} =-cos\,x+C\\y=-x\,cos\,x+Cx$

Here, C is a constant.

Transient term is a term such that it tends to 0 as x → ∞

Here, there does not exist any term that tends to 0 as x → ∞

So, there are no transient terms.

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3 years ago

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C
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