Answer:
The bearing is N 55.62° W
Step-by-step explanation:
ship leaves the port of Miami with a bearing of S80°E and a speed of 15 knots.
It then turns 90° towards the south after one hour.
Still maintain the same speed and direction for two hours.
The bearing is just the angle difference from the ship current location to where it started.
Let the speed be km/h
Distance covered in the first round
= 15*1
= 15km
Distance covered in the second round
=15*2
= 30 km
Angle at C = (90-80)+90
Angle at C = 10+90= 100
Let the distance between the port and the ship be c
C²= a² + b² -2abcos
C²= 15²+30²-2(15)(30)cos 100
C²= 225+900+156.28
C²= 1281.28
C= 35.8 km
Using sine formula
30/sin x= 35.8/sin 100
30/35.8 * sin 100 = sinx
0.838*0.9848= sin x
0.8253= sin x
Sin ^-1 0.8253 = x
55.62° = x
The bearing is N 55.62° W
To be able to arrange the volumes from least to greatest we must be mindful that the exponent of 10 in the scientific notation should be arranged from least to greatest also. If two or more items have the same exponents in the 10 of the scientific notation, we use the base for comparison. For this item, the arrangement should be
2.2x10^12 km³, 6.9x10^12 km³, 2.7x10^18 km³, and 4.9x10^21 km³
Thus, the answer to this item is letter B.
Answer:
Step-by-step explanation:
A) From the order of the exercise we already know that the intersection points lies on the Y-axis, so its coordinates are P(0;y;0). In order to find it, we only need to substitute the equation 4x+4z=0 into the equation 4x+3y+4z=1. Then,
1=4x+3y+4z = 3y + (4x+4z)= 3y+0.
From the expression above it is easy to obtain that y=1/3, and the intersection point is P(0;1/3;0).
B) To obtain the parallel vector to both planes we use the cross product of the normal vector of the planes.
![\left[\begin{array}{ccc}i&j&k\\4&3&4\\4&0&4\end{array}\right] = 12i-0j+12k](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C4%263%264%5C%5C4%260%264%5Cend%7Barray%7D%5Cright%5D%20%3D%2012i-0j%2B12k)
As we want a unit vector, we must calculate the modulus of u:
.
Thus, the wanted vector is 
. Therefore,
.
C) In order to obtain the vector equation of the intersection line of both planes, we just need to put together the above results.
where 
is a real number.
Answer:
12 square units
Step-by-step explanation:
(Base x height)/2
(6*4)/2=12
Answer:
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