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jok3333 [9.3K]
3 years ago
15

Write an equation of a line in slope intercept form that is perpendicular to y = -4x -2 and passes through the point (-16, -11).

Mathematics
1 answer:
NISA [10]3 years ago
4 0
Y = -4x - 2
P (-16, -11)
a = -4, b = 0, c = -2
m = -a/b
m = -(-4)/(-2)
m = 4/(-2)
m = -2

y-yo = m(x-xo)
y-(-11) = -2[x-(-16)]
y+11 = -2(x+16)
y+11 = -2x-32
2x+y+11+32 = 0
2x+y+43 = 0

A outra questão é semelhante.
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Remember that

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Verify each option

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x=1, y=1/2

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N 3

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Step-by-step explanation:

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Read 2 more answers
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Oksana_A [137]

Answer:

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Step-by-step explanation:

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To solve this correctly you must to add the coefficients of the like terms (terms who has same variables or constant terms)

∵ 13x , 17x , x are like terms ⇒ terms with same variable

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∴ (13x + 17x + x) + (5 - 4.5) = 31x + 0.5

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* <u>The error of second answer:</u>

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* <u>The error of third answer:</u>

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Answer:

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Step-by-step explanation:

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