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3 years ago

State the leading coefficient of -7x+10x^3-9x^5+3x^2+3?

Mathematics

1 answer:

Anika [276]3 years ago

5 0

Answer:

-9

Step-by-step explanation:

-7x+10x^3-9x^5+3x^2+3

We need to write the terms from highest power to smallest power

-9x^5+10x^3+3x^2-7x+3

The leading coefficient is the number in front of the highest power

-9

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PLZ HELP!!

ludmilkaskok [199]

9514 1404 393

Answer:

y = -3x^2 -9x +30

Step-by-step explanation:

When a polynomial has a zero at x=p, it has a factor of (x -p). The factors of your quadratic are ...

f(x) = (x +5)(x -2)

At the point x=3, the value of this product is ...

f(3) = (3 +5)(3 -2) = (8)(1) = 8

In order for that value to be -24, it needs to be multiplied by a scale factor of -3. The quadratic you want is ...

y = -3(x +5)(x -2)

y = -3x^2 -9x +30 . . . . . standard form

3 0

3 years ago

If A and B are independent events with P( A) = 0.60 and P( A| B) = 0.60, then P( B) is: a. 0.60 b. cannot be determined with the

Simora [160]

Answer:

<h2>B. cannot be determined</h2>

Step-by-step explanation:

For two events A and B to be independent, it means they can occur at the same time i.e the occurrence of one does not affect the other occurring. It is represented as P(A∩B) = P(A)P(B)

Given P( A) = 0.60 and P( A| B) = 0.60, to find P(B), we will use the formula for the conditional probability P( A| B) = P(A∩B) /P(B)

P( A| B) = P(A)P(B) /P(B)

P( A| B) = P(A)

Since P( A| B) = 0.60, therefore P(A) is also equal to 0.60 and P(B) cannot be determined since they cancelled out already

7 0

3 years ago

Does the scatter plot 11

GarryVolchara [31]

Answer: no correlation .C

Step-by-step explanation: there is no correlation if the change on X has no impact on Y

hope this helped

5 0

1 year ago

Suiting at 6 a.m., cars, buses, and motorcycles arrive at a highway loll booth according to independent Poisson processes. Cars

dem82 [27]

Answer:

Step-by-step explanation:

From the information given:

the rate of the cars = $\dfrac{1}{5} \ car / min = 0.2 \ car /min$

the rate of the buses = $\dfrac{1}{10} \ bus / min = 0.1 \ bus /min$

the rate of motorcycle = $\dfrac{1}{30} \ motorcycle / min = 0.0333 \ motorcycle /min$

The probability of any event at a given time t can be expressed as:

$P(event \ (x) \ in \ time \ (t)\ min) = \dfrac{e^{-rate \times t}\times (rate \times t)^x}{x!}$

∴

(a)

$P(2 \ car \ in \ 20 \ min) = \dfrac{e^{-0.20\times 20}\times (0.2 \times 20)^2}{2!}$

$P(2 \ car \ in \ 20 \ min) =0.1465$

$P ( 1 \ motorcycle \ in \ 20 \ min) = \dfrac{e^{-0.0333\times 20}\times (0.0333 \times 20)^1}{1!}$

$P ( 1 \ motorcycle \ in \ 20 \ min) = 0.3422$

$P ( 0 \ buses \ in \ 20 \ min) = \dfrac{e^{-0.1\times 20}\times (0.1 \times 20)^0}{0!}$

$P ( 0 \ buses \ in \ 20 \ min) = 0.1353$

Thus;

P(exactly 2 cars, 1 motorcycle in 20 minutes) = 0.1465 × 0.3422 × 0.1353

P(exactly 2 cars, 1 motorcycle in 20 minutes) = 0.0068

(b)

the rate of the total vehicles = 0.2 + 0.1 + 0.0333 = 0.3333

the rate of vehicles with exact change = rate of total vehicles × P(exact change)

$= 0.3333 \times \dfrac{1}{4}$

= 0.0833

∴

$P(zero \ exact \ change \ in \ 10 minutes) = \dfrac{e^{-0.0833\times 10}\times (0.0833 \times 10)^0}{0!}$

P(zero exact change in 10 minutes) = 0.4347

The probability of the 7th motorcycle after the arrival of the third motorcycle is:

$P( 4 \ motorcyles \ in \ 45 \ minutes) =\dfrac{e^{-0.0333\times 45}\times (0.0333 \times 45)^4}{4!}$

$P( 4 \ motorcyles \ in \ 45 \ minutes) =0.0469$

Thus; the probability of the 7th motorcycle after the arrival of the third one is = 0.0469

P(at least one other vehicle arrives between 3rd and 4th car arrival)

= 1 - P(no other vehicle arrives between 3rd and 4th car arrival)

The 3rd car arrives at 15 minutes

The 4th car arrives at 20 minutes

The interval between the two = 5 minutes

<u>For Bus:</u>

P(no other vehicle other vehicle arrives within 5 minutes is)

= $\dfrac{6}{12} = 0.5$

<u>For motorcycle:</u>

$= \dfrac{2 }{12} = \dfrac{1 }{6}$

∴

The required probability = $1 - \Bigg ( \dfrac{e^{-0.5 \times 0.5^0}}{0!} \times \dfrac{e^{-1/6}\times (1/6)^0}{0!} \Bigg)$

= 1- 0.5134

= 0.4866

6 0

3 years ago

Three times a number, minus 5 is equal to two times the number, plus 7

vitfil [10]

3x - 5 = 2x + 7 i call the number "x"
3x = 2x + 12
1x = 12
x = 12 the number is 12

6 0

4 years ago