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Semenov [28]
3 years ago
10

Transversal t cuts parallel lines a and b as shown in the diagram. Which equation is necessarily true? a) m<1=m<2 b)m<4

=m<6 c) m<3+m<5=90 degrees d)m<7=m<8
Mathematics
2 answers:
notka56 [123]3 years ago
7 0

Answer:

answer is D

Step-by-step explanation:

lara31 [8.8K]3 years ago
6 0
If the numbering of the angles is similar to this:
1 | 2
-----
3 | 4
5 | 6
----
7 | 8

Then none of the the choices are necessarily true.

The equations would have been:
1 = 4 = 5 = 8
2 = 3 = 6 = 7
3 + 5 = 4 + 6 = 180


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Answer:

$17.85792

Step-by-step explanation:

$0.4544 x 39.3 = $17.85792

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What is the experimental probability of the spinner landing on red?.
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Answer:

The chances of landing on red are 1 in 4, or one fourth. This problem asked us to find some probabilities involving a spinner

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6 0
1 year ago
Hitung jarak di antara titik P(7, 1) dengan titik Q(7, 8) ​
MaRussiya [10]

Answer:

7 units

Step-by-step explanation:

Distance between 2 points

=\sqrt{(y1 - y2)^{2}  + (x1 - x2) {}^{2} }

Thus, distance PQ

=\sqrt{(8 - 1)^{2}  + (7 - 7)^{2} }  \\ = \sqrt{7^{2} }  \\  = 7

Or you could simply take 8-1= 7 since both points have the same x-coordinate. Thus, PQ is a vertical line and the distance between them is due to the difference in their y-coordinate.

5 0
3 years ago
Please answer correctly! I will mark you Brainliest! The pictures go together! Please No answering without knowing answer or sca
Anna007 [38]

Answer:

904.32

Step-by-step explanation:

\frac{4}{3}\cdot \:3.14\cdot \:6^3=904.32

The volume of a sphere is \frac{4}{3}\pir^{3}

6 0
2 years ago
SOLVING EACH SYSTEM BY ELIMINATION <br><br><br> x+3y=5 x=-6y+14<br><br><br> HELP
nata0808 [166]

Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

Step-by-step explanation:

Given the system of the equations

x+3y=5;\:x=-6y+14

solving by elimination method

\begin{bmatrix}x+3y=5\\ x=-6y+14\end{bmatrix}

\mathrm{Arrange\:equation\:variables\:for\:elimination}

\begin{bmatrix}x+3y=5\\ x+6y=14\end{bmatrix}

x+6y=14

-

\underline{x+3y=5}

3y=9

\begin{bmatrix}x+3y=5\\ 3y=9\end{bmatrix}

solve 3y=9 for y:

3y=9

\frac{3y}{3}=\frac{9}{3}

y=3

\mathrm{For\:}x+3y=5\mathrm{\:plug\:in\:}y=3

Solve x+3\cdot \:3=5 for x:

x+3\cdot \:3=5

x+9=5

x=-4

Therefore,

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

6 0
2 years ago
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