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bezimeni [28]
3 years ago
15

Students at Dessau Middle School can have fun with math at their first Olympic Math Game Night. It is scheduled for 6 to 8 p.m.

on Thursday in the school gym. Students will compete in math-related games with the encouragement of their parents. Pizza will be available in the cafeteria. The Austin Astronomical Society will bring its telescopes for stargazing in the parking lot.
The event is designed to take away some of the fear of math in preparation for the April 16 state-wide math test. It is free and open to parents and students at Dessau Middle School. For more information, call the school at 989-5891. Ask for teacher Marsha McNeill.

Which is the best way to summarize this passage?
A.
Students at Dessau Middle School will take a state-wide math test on April 16. For more information, call teacher Marsha McNeill at Dessau Middle School by Thursday.
B.
Students at Dessau Middle School will enjoy math-related games, pizza, and stargazing on Thursday night. The Austin Astronomical Society will bring the telescopes.
C.
Dessau Middle School is offering a night of fun math-related activities on Thursday from 6 to 8 p.m. They will help ease students' fears about taking the state math test.
D.
Teachers at Dessau Middle School really care about how their students do on the state-wide math test. That is why they want to get parents involved in homework.
Mathematics
2 answers:
galina1969 [7]3 years ago
4 0

Answer:

great essay lol

Step-by-step explanation:

Marrrta [24]3 years ago
4 0

Answer:

C is the answer Dessau Middle School is offering a night of fun math-related activities on Thursday from 6 to 8 p.m. They will help ease students' fears about taking the state math test.

Step-by-step explanation:

i just got it

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In a class⅗ of the children are going to special event If there are 30 children in the class,how many are going​
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18

Step-by-step explanation:

3/5 x 30

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Hope this helps:-)

4 0
3 years ago
Marni has 11 ounces of walnuts. She needs 6 ounces for one recipe and pound for another. There are 16 ounces in 1 pound.
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11-6=5 ounces. She doesn’t have enough for both of the recipes. She will need 11 more ounces to be able to make the recipes. 5+11=16 and 16 ounces are in a pound.
4 0
2 years ago
Read 2 more answers
Your bank account is sitting on $14,000. You started with a principal balance of $12,500. If the interest rate was 4.5% compound
Simora [160]

Answer:

t=2.5\ years  

Step-by-step explanation:

we know that

The formula to calculate continuously compounded interest is equal to

A=P(e)^{rt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest in decimal  

t is Number of Time Periods  

e is the mathematical constant number

we have  

t=?\ years\\ P=\$12,500\\P=\$14,000\\ r=4.5\%=4.5/100=0.045  

substitute in the formula above   and solve for t

14,000=12,500(e)^{0.045t}  

Simplify

14,000/12,500=(e)^{0.045t}  

1.12=(e)^{0.045t}  

Apply ln both sides

ln(1.12)=ln[(e)^{0.045t}]  

ln(1.12)=(0.045t)ln(e)  

Remember that

ln(e)=1  

so

ln(1.12)=(0.045t)  

t=ln(1.12)/(0.045)  

t=2.5\ years  

3 0
3 years ago
Carrie has a stamp collection she is very proud of. She buys a frame to display her favorite stamps. The frame is 6 inches wide,
olga55 [171]
The stamps should be .85 inches each
7 0
2 years ago
If <img src="https://tex.z-dn.net/?f=%5Crm%20%5C%3A%20x%20%3D%20log_%7Ba%7D%28bc%29" id="TexFormula1" title="\rm \: x = log_{a}(
timama [110]

Use the change-of-basis identity,

\log_x(y) = \dfrac{\ln(y)}{\ln(x)}

to write

xyz = \log_a(bc) \log_b(ac) \log_c(ab) = \dfrac{\ln(bc) \ln(ac) \ln(ab)}{\ln(a) \ln(b) \ln(c)}

Use the product-to-sum identity,

\log_x(yz) = \log_x(y) + \log_x(z)

to write

xyz = \dfrac{(\ln(b) + \ln(c)) (\ln(a) + \ln(c)) (\ln(a) + \ln(b))}{\ln(a) \ln(b) \ln(c)}

Redistribute the factors on the left side as

xyz = \dfrac{\ln(b) + \ln(c)}{\ln(b)} \times \dfrac{\ln(a) + \ln(c)}{\ln(c)} \times \dfrac{\ln(a) + \ln(b)}{\ln(a)}

and simplify to

xyz = \left(1 + \dfrac{\ln(c)}{\ln(b)}\right) \left(1 + \dfrac{\ln(a)}{\ln(c)}\right) \left(1 + \dfrac{\ln(b)}{\ln(a)}\right)

Now expand the right side:

xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} \\\\ ~~~~~~~~~~~~+ \dfrac{\ln(c)\ln(a)}{\ln(b)\ln(c)} + \dfrac{\ln(c)\ln(b)}{\ln(b)\ln(a)} + \dfrac{\ln(a)\ln(b)}{\ln(c)\ln(a)} \\\\ ~~~~~~~~~~~~ + \dfrac{\ln(c)\ln(a)\ln(b)}{\ln(b)\ln(c)\ln(a)}

Simplify and rewrite using the logarithm properties mentioned earlier.

xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} + \dfrac{\ln(a)}{\ln(b)} + \dfrac{\ln(c)}{\ln(a)} + \dfrac{\ln(b)}{\ln(c)} + 1

xyz = 2 + \dfrac{\ln(c)+\ln(a)}{\ln(b)} + \dfrac{\ln(a)+\ln(b)}{\ln(c)} + \dfrac{\ln(b)+\ln(c)}{\ln(a)}

xyz = 2 + \dfrac{\ln(ac)}{\ln(b)} + \dfrac{\ln(ab)}{\ln(c)} + \dfrac{\ln(bc)}{\ln(a)}

xyz = 2 + \log_b(ac) + \log_c(ab) + \log_a(bc)

\implies \boxed{xyz = x + y + z + 2}

(C)

6 0
2 years ago
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