All categories

3 years ago

What is the value of b

Mathematics

1 answer:

n200080 [17]3 years ago

7 0

Angle = 68⁰ is an inscribed angles, this angle equal 68⁰,

so it intersect arc = 2*68⁰= 136⁰.

Arc of the whole circle (circumference) =360⁰,and it also =b+104+136.

b+104+136 =360

b=360-(104+136) = 120⁰

Answer A. b=120⁰.

You might be interested in

The sum of a number and its reciprocal is 5/2 Find the number and its reciprocal.

sergiy2304 [10]

Answer:

Step-by-step explanation:

Let the number be 'x'

Reciprocal = $\frac{1}{x}$

$x+\frac{1}{x}=\frac{5}{2}\\\\\frac{x*x}{1*x}+\frac{1}{x}=\frac{5}{2}\\\\\frac{x^{2}+1}{x}=\frac{5}{2}$

Cross multiply

(x² + 1) *2 = 5*x

2x² + 2 = 5x

2x² - 5x + 2 =0

Factorize the equation,

Sum = -5

Product = 4

Factors = -1 , -4

2x² - x - 4x + 2 = 0

x(2x - 1) - 2(2x - 1) = 0

(2x -1 )(x - 2) = 0

2x - 1 = 0 ; x -2 = 0

2x =1 ; x = 2

x = 1/2

Number = 2 , and its reciprocal = 1/2

6 0

3 years ago

Ben drinks tea at an incredible rate.He drinks 3 1/2 liters of tea every 2/3 of an hour.Ben drinks tea a constant rate.How many

vampirchik [111]

Answer:

Step-by-step explanation:

2/3 = 0.66

1 hour = 60

60 x 0.66 = 39.6 or 40

In which, 60 - 40 = 20; so he only drinks 3 1/2 liters every 40 minutes.

He drinks 3 1/2 every hour.

3 0

3 years ago

In triangle CAP if c=7, a=6 and cosP = -3/7, find p

Oliga [24]

The P right there you put = -3/7 after it

3 0

3 years ago

Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min, and its coarseness is such that it forms a pile in the shap

11Alexandr11 [23.1K]

Answer:

0.25 feet per minute

Step-by-step explanation:

Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min. Since we are told that the shape formed is a cone, the rate of change of the volume of the cone.

$\dfrac{dV}{dt}=20$ ft^3/min$

$\text{Volume of a cone}=\dfrac{1}{3}\pi r^2 h$

Since base diameter = Height of the Cone

Radius of the Cone = h/2

Therefore,

$\text{Volume of the cone}=\dfrac{\pi h}{3} (\dfrac{h}{2}) ^2 \\V=\dfrac{\pi h^3}{12}$

$\text{Rate of Change of the Volume}, \dfrac{dV}{dt}=\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}$

Therefore: $\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}=20$

We want to determine how fast is the height of the pile is increasing when the pile is 10 feet high.

$h=10$ feet$\\\\\dfrac{3\pi *10^2}{12}\dfrac{dh}{dt}=20\\25\pi \dfrac{dh}{dt}=20\\ \dfrac{dh}{dt}= \dfrac{20}{25\pi}\\ \dfrac{dh}{dt}=0.25$ feet per minute (to two decimal places.)$

When the pile is 10 feet high, the height of the pile is increasing at a rate of 0.25 feet per minute

5 0

3 years ago

Nancy is running on a trail that's 5.3 miles long. After 20 minutes, she has run 1.45 miles. Write an addition to fine how much

mars1129 [50]

Answer:

5.3-1.45=3.85

Step-by-step explanation:

she has 3.85 miles left to go because she already ran 1.45 and if you subtract that from the 5.3 you get 3.85 left to run.

5 0

3 years ago