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3 years ago

7

What is 1/3 + 1/2?.......

2 answers:

Gelneren [198K]3 years ago

6 0

Answer:

This answer is soo easy:)

Step-by-step explanation:

1/3+1/2=5/6. Plze mark brainiest:)

Virty [35]3 years ago

3 0

Answer:

5/6

Step-by-step explanation:

1/3 + 1/2 = 5/6

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(14x2 - 3x3 + 9x4) - (-14 + 13x3 + 11x4) simplify and answer in standard form

FromTheMoon [43]

We have that
(14x2 - 3x3 + 9x4) - (-14 + 13x3 + 11x4)=<span>14x2 - 3x3 + 9x4 +14 - 13x3 - 11x4
</span>(14x2 - 16x3 +14 - 2x4)

then
-2x4-16x3+14x2+14=0--------------> this is the <span>standard form

simplify </span><span>dividing the entire expression by two
</span><span>-x4-8x3+7x2+7=0

the answer is
</span>-x4-8x3+7x2+7=0<span>

</span>

4 0

3 years ago

I will give brainliest answer

dalvyx [7]

Answer:

4 right; 4 up

Step-by-step explanation:

The difference between the two points is ...

P'(1, 5) -P(-3, 1) = (1-(-3), 5-1) = (4, 4)

The translation is 4 units to the right and 4 units up.

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3 years ago

Time Sensitive Question

Anika [276]

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X< 7/12

Step-by-step explanation:

5 0

3 years ago

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Which type of triangle has 2 angles that measures 45?

dlinn [17]

Answer: it's obtuse. Yep

Step-by-step explanation:

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3 years ago

According to data from a medical association, the rate of change in the number of hospital outpatient visits, in millions, in

GaryK [48]

Answer:

a) $f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000$

b) f(t=2015) = 264,034,317.7

Step-by-step explanation:

The rate of change in the number of hospital outpatient visits, in millions, is given by:

$f'(t)=0.001155t(t-1980)^{0.5}$

a) To find the function f(t) you integrate f(t):

$\int \frac{df(t)}{dt}dt=f(t)=\int [0.001155t(t-1980)^{0.5}]dt$

To solve the integral you use:

$\int udv=uv-\int vdu\\\\u=t\\\\du=dt\\\\dv=(t-1980)^{1/2}dt\\\\v=\frac{2}{3}(t-1980)^{3/2}$

Next, you replace in the integral:

$\int t(t-1980)^{1/2}=t(\frac{2}{3}(t-1980)^{3/2})- \frac{2}{3}\int(t-1980)^{3/2}dt\\\\= \frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}+C$

Then, the function f(t) is:

$f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+C'$

The value of C' is deduced by the information of the exercise. For t=0 there were 264,034,000 outpatient visits.

Hence C' = 264,034,000

The function is:

$f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000$

b) For t = 2015 you have:

$f(t=2015)=0.001155[\frac{2}{3}(2015)(2015-1980)^{1/2}-\frac{4}{15}(2015-1980)^{5/2}]+264,034,000\\\\f(t=2015)=264,034,317.7$

3 0

3 years ago