Answer:
Explanation:
T=fd
f=170N
d=0.155m
T=170*0.155
T=26.35Nm⁻
i don't know how to convert to pound foot
the answer is correct in newton meters anyway(Nm⁻¹)
The isotopes half life is 2 hours
Since given the following :
time = 8 hours × 3600s/hr = 28800 seconds
A₀ = 80 Bq as the first registration of detector counts per second
A = 5 Bq as the registration of detector counts per second eight hours later
Using the formula:
∴ A = A₀ e^-λt
∴ A/A₀ = e^-λt
∴ ln (A/A₀) = -λt
∴ λ = -ln (A/A₀) /t = ln2 / t_{1/2}
∴ t_{1/2} = -ln2 / ln(A/A₀) (t)
∴ t_{1/2} = -ln2 / ln(5/80) (8 hours) = 2 hours
Answer:
I = 0.25 AND T= 4 HOURS, Q = ??
multiply both min and sec , 240 and 60
we get 1400 sec
the formula for current is I = Q/T
substitute the given data in the formula and simplify it
so , Q = 3600C
Answer:
Explanation:
Capacitance of the capacitor
C = ε₀ A / d
(8.85 x 10⁻¹² x .25² x 10⁻⁴) / 1 x 10⁻³
C = .553125 x 10⁻¹³ F
Charge = capacitance x volt
= .553125 x 10⁻¹³ x 1.5
= .8296875 x 10⁻¹³ C
no of electrons
= charge / charge on one electron
= .8296875 10⁻¹³/ 1.6 x 10⁻¹⁹
= 5.2 x 10^5
Answer:
8.2N
Explanation:
I took the test and got it right :)
