Ask question

Ask question

All categories

Norma-Jean [14]

3 years ago

11

A bicyclist is in a 50-km race. She says she had an average velocity of 35. What is missing in the cyclist's velocity? A. units

only B. units and distance C. direction only D. units and direction

2 answers:

mixas84 [53]3 years ago

7 0

Answer: A

I hope this helped and have a wonderful day!!

aivan3 [116]3 years ago

4 0

Hello There!

It is A. Units only.

Hope This Helps You!
Good Luck :)

- Hannah ❤

You might be interested in

Which stage follows the red giant stage of star development, if the star is a high-mass star?

Anestetic [448]

I believe it's a supernova

3 0

3 years ago

Just how small do you think an individual atom is

jok3333 [9.3K]

An atom is probably less than 1 nano-meter in size

8 0

3 years ago

Read 2 more answers

Calculate the speed of a proton after it accelerates from rest through a potential difference of 380 v .

nikitadnepr [17]

The magnitude of the change in potential energy is equal to the kinetic energy,

$\left | \Delta U \right |= K$

or

$qV=\frac{1}{2} mv^{2}$

Here, V is potential difference, q is charge, m is mass and v is velocity.

We can also write,

$v=\sqrt{\frac{2qV}{m} }$

Given $V=380 V$

Substituting this value with mass of proton, $m=1.672\times10^{-27} kg$ and charge of proton, $q= 1.6\times10^{-19} C$ we get

$v=\sqrt{\frac{2\times1.6\times10^{-19}C \times 380V}{1.672\times10^{-27} kg} }\\\\v= 727.27\times10^{8} m/s =7.27\times10^{6}m/s$

Therefore, the speed of proton is $7.27\times10^{6}m/s$ .

7 0

3 years ago

Read 2 more answers

A)If your torsion balance deflects to an angle of 10° when your two spheres are 40cm apart, what angle will it deflect to when t

svp [43]

Answer:

Explanation:

Given

for $\theta=10^{\circ}$

Sphere are $d=40\ cm$

when sphere $d_2=10\ cm$ apart suppose deflection is $\theta _2$

We know

$F=k_t\cdot \theta$

Where F=force between charged particle

$\theta =$ Deflection

$F=\frac{kQ_1Q_2}{r^2}=k_t\cdot \theta$

$\theta =\frac{k}{k_t}\times \frac{Q_1Q_2}{r^2}----1$

thus $\theta \propto \frac{1}{r^2}$

for $\theta _2$

$\frac{\theta _1}{\theta _2}=(\frac{r_2}{r_1})^2$

$\theta _2=16\times \theta _1$

$\theta _2=160^{\circ}$

(b)for $10^{\circ}$ deflection Potential $v_1=8\ kV$

Electric Potential is $V=\frac{kQ}{r}$

$Q=\frac{V\cdot r}{k}$

where V=voltage

k=constant

r=distance between charges

Put value of Q in equation 1

$\theta =\frac{k}{k_t}\times \frac{V^2r^2}{k^2}$

$\theta =\frac{V^2r^2}{k\cdot k_t}$

thus $\theta \propto V^2$

therefore

$\frac{\theta _1}{\theta _2}=(\frac{V_1}{V_2})^2$

$\frac{10}{\theta _2}=(\frac{8}{4})^2$

$\theta _2=\frac{10}{4}=2.5^{\circ}$

5 0

2 years ago

How does the sun impact land at different latitudes?

Masja [62]

The radiation of the solar rays of the sun can damage and heat up land closer but at the same time cool because of the atmosphere

5 0

2 years ago