A matchstick has a lot of chemical energy stored in it. When the match is struck, it burns and the chemical energy in it produces heat energy and light energy.
Shortwave radios have a higher frequency than ultraviolet light
Answer:
a) v=2.743m/s
b) 
c) T=2.543N
Explanation:
First, calculate the height of the ball at the starting point:


At this point, just in the moment the ball is released, all the energy of the system is potencial gravitational energy. When it is at the bottom all the potencial energy is transformed into kinetic energy:

Solving for v:

if h is the height loss: (l-y')
v=2.743m/s
The centripetal acceleration is the acceleration caused by the tension force exercised by the string, and is pointing outside of the trayectory path (at the lowest point, directly dawn):


To calculate tension, just make the free body diagram of forces in the ball, noticing the existence of the centripetal acceleration:

Explanation:
When neutral objects are placed in the vicinity of charged objects,they get attracted.
The isolated neutral object has positive charge and negative charge spread throughout it completely.
When a charged particle is brought,the opposite charges in the neutral object occupy the positions near to the charged particle and the like charges occupy the positions far from the charged particle.
This creates a dipole with some dipole moment.
This dipole attracts to the field of the charged particle.
Sorry I honestly don’t know that answer