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Rus_ich [418]
3 years ago
7

3x+1/5y=7. Solve for y.

Mathematics
1 answer:
dedylja [7]3 years ago
7 0
3x+1/5y=7
-3x           -3x
1/5y=7-3x
-1      -1
5y=6-3x
---   -----
5       5

y = 6-3x
      ------
         5

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32000 and 500 , so the number 32000 has three 0 and 500 2 , so you can take off two 0 from 32000, which equals to 320 .You have to find a number that times 5 equals 320 or almost , the most approaching number is 6 , because 5 times 6 equals 30 , then you have to subtract, the result of the subtraction is 2 , 2 is less than 5 so we have to put a zero , so we got 20 , which number times 5 can give you 20 ? , 4 , so your answer is 64 .
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svlad2 [7]

4x - y = 3

y = 2x + 13


Substitute the second equation into the first equation:

4x - y = 3  [since y = 2x + 13, you can substitute (2x + 13) for "y" in the equation]

4x - (2x + 13) = 3    Distribute/multiply - into (2x + 13)

4x - 2x - 13 = 3  

2x - 13 = 3       Add 13 on both sides

2x = 16     Divide 2 on both sides

x = 8


Now that you know x = 8, plug it into one of the equations to find y

y = 2x + 13

y = 2(8) + 13

y = 16 + 13

y = 29


x = 8, y = 29  or  (8, 29)


[proof]

4x - y = 3

4(8) - 29 = 3

32 - 29 = 3

3 = 3


y = 2x + 13

29 = 2(8) + 13

29 = 16 + 13

29 = 29


7 0
3 years ago
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