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Keith_Richards [23]
3 years ago
7

In a graduation program,1 1/2 hours are set aside for speakers. If the keynote speaker is given 1/4 hour, how long will each of

the remaining 5 speakers have to give their speech?
Mathematics
2 answers:
xeze [42]3 years ago
8 0
Okay. So the keynote speaker has 1/4 of an hour to speak, which means that 1 1/4 hours or 75 minutes are left for speakers. To find out the amount of time for each of the remaining 5 speakers, you have to divide 75 by 5. 75/5=15. The remaining 5 speakers will have 15 minutes to give their speech.
Anuta_ua [19.1K]3 years ago
4 0
1 1/2 -1/4 = 5/4 remaining
5/4 divided by 5 = 1/4 per remaining speaker
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140 fluid ounces increased by 45%
Stels [109]
Hello!

"Increase" means to add. We must find out what 45% of 140 fluid ounces is, and to do that we must first convert the percentage to a decimal and then multiply it by the amount of fluid ounces.

I know, that's probably a lot to take in! :D

45% ÷ 100 = 0.45 as a decimal

0.45 × 140 = 63

Add this to the amount of fluid ounces:

140 + 63 = 203

Final Answer:

203 fluid ounces.
5 0
3 years ago
Read 2 more answers
hi i'm really struggling with this and its due later today! If someone could show the work of how to do it and the answer that w
GuDViN [60]

Answer:

\frac{-5 \pm \sqrt{13} }{6}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\frac{-5 \pm \sqrt{5^2-4(3)(1)} }{2(3)}<u />

<u />

<u>Step 2: Evaluate</u>

  1. Evaluate Exponents:                    \frac{-5 \pm \sqrt{25-4(3)(1)} }{2(3)}
  2. Evaluate Multiplication:               \frac{-5 \pm \sqrt{25-12} }{6}
  3. Evaluate Subtraction:                  \frac{-5 \pm \sqrt{13} }{6}
8 0
3 years ago
Help me find the mean mode range median
pashok25 [27]

Answer:

Mean=2.53

median=2

mode=2

range=3

Step-by-step explanation:

1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 4

MEAN

Add up all data values to get the sum

Count the number of values in your data set

Divide the sum by the count

38/15=2.53

MEDIAN

Arrange data values from lowest to the highest value

The median is the data value in the middle of the set

If there are 2 data values in the middle the median is the mean of those 2 values.

MODE

Mode is the value or values in the data set that occur most frequently.

RANGE

18-15=3

5 0
3 years ago
What is .84 divided by .02<br> please help me because i really really REALLY need help on this
KatRina [158]

Hello There!

.84 ÷ .02 ≈ 42

WORK SHOWN IN IMAGE ATTACHED

3 0
3 years ago
The diameters of ball bearings are distributed normally. The mean diameter is 83 millimeters and the standard deviation is 3 mil
Alenkinab [10]

Answer:

0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 83, \sigma = 3

Find the probability that the diameter of a selected bearing is greater than 85 millimeters.

This is 1 subtracted by the pvalue of Z when X = 85. Then

Z = \frac{X - \mu}{\sigma}

Z = \frac{85 - 83}{3}

Z = 0.67

Z = 0.67 has a pvalue of 0.7486.

1 - 0.7486 = 0.2514

0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.

7 0
3 years ago
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