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Zanzabum
3 years ago
15

Which algebraic rule describes the transformation of triangle ABC to A’B’C’

Mathematics
1 answer:
Rasek [7]3 years ago
6 0

Answer:

T(0, –3)

Step-by-step explanation:

triangle ABC was translated down 3 points, so if you subtract 3 from each of ABC's points, you'll get triangle A'B'C'

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Simplify the expression.<br> (x 3/2)6
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For this case we must simplify the following expression:

(x ^ {\frac {3} {2}}) ^ 6

We have that by definition of properties of powers that is fulfilled:

(a ^ n) ^ m = a ^ {n * m}

Then, rewriting the expression:

x ^ {\frac {3 * 6} {2}} =\\x ^ {\frac {18} {2}} =\\x ^ 9

Answer:

(x^{\frac{3}{2}})^6=x^9

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The answer would be $104.5 
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Write out the first few terms of the series Summation from n equals 0 to infinity (StartFraction 2 Over 3 Superscript n EndFract
anyanavicka [17]

Answer:

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = 15/8

Step-by-step explanation:

The sum you are trying to understand is this.

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n}

Remember that in general when you have a geometric series  

\sum\limits_{n = 0}^{\infty} a*r^n you have that

\sum\limits_{n = 0}^{\infty} a*r^n = \frac{a}{1-r}      and that equality is true as long as     |r| < 1.

Therefore here we have

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{3*5} \big)^n = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n        and   \big|\frac{-1}{15} \big| = \frac{1}{15} < 1

Therefore we can use the formula and

\sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n =  \frac{2}{1-(-1/15)} = \frac{2}{1+1/15} = 30/16  = 15/8

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3 years ago
If a person high jumps 6 feet 8 inches, how many inches is the jump?
LenaWriter [7]

Answer:

80 inches

Step-by-step explanation:

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